Let the lengths of EH and FG = x
Let the lengths of EF and HG = x-5
Solve,
X + X + (X-5) + (X-5) = 48
4X - 10 = 48
4X = 58
X = 14.5
EH= 14.5
FG = 14.5
EF = 9.5
HG = 9.5
Answer:
2.86%
Step-by-step explanation:
assuming there is no replacement
There is a total of 6 envelopes
Since the question is asking for red, then green, then red, order is very important
The probability of a red is 3/7
Since we have selected 1 envelope, there are only 6 total envelopes left so the probability of a green is 1/6
Then we need a red again
Since we have selected 2 envelopes, one of which is red, there are only 5 total envelopes and 2 red envelopes so the probability of a red is 2/5
Now we multiply all of these so 3/7x1/6x2/5 = .02857142857
To find the percentage, you multiply by 100 so 2.857142857
Im pretty sure they want you to estimate it so 2.86% is what I would put but it depends on your teacher
Answer:
They are the two variables in the equation. They could will have different or the same values, but are seperate mathematical and logical entities.
Answer:
1. Proved down
2. proved down
3. f(10) = -20 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5
Step-by-step explanation:
Let us explain how to solve the question
∵ f(0) = -20, f(n) = f(n - 1) - 5 for n > 1
→ That means we have an arithmetic sequence with constant
difference -5 and first term -20
1. → f(1) means we need to find the second term, which equal the
term - 5
∵ f(1) means n = 1
∴ f(1) = f(1 - 1) - 5
∴ f(1) = f(0) - 5
∵ f(0) = -20
∴ f(1) = -20 - 5 → Proved
2. → f(3) means we need to find the third term, which equal the
second term - 5
∵ f(3) means n = 3
∴ f(3) = f(3 - 1) - 5
∴ f(3) = f(2) - 5
→ f(2) = f(1) - 5
∵ f(1) = -20 - 5
∴ f(2) = [-20 - 5] - 5 = -20 - 5 - 5
∴ f(3) = [-20 - 5 - 5] - 5
∴ f(3) = -20 - 5 - 5 - 5 → Proved
3. → From 1 and 2 we notice that the number of -5 is equal to n,
at n = 1 there is one (-5), when n= 3 there are three (-5)
∵ n = 10
∴ There are ten (-5)
∴ f(10) = -20 - 5(10)
∴ f(10) = -20 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 - 5 → Proved
