Your answer is going to be 4/9 :)
I don't really understand this, could anyone possibly help me?
1 answer:
We have to name a line that "contains" point P. This means that we have to find a line that passes through point P. We can see that line PS/n goes through point P.
We have to find the plane's name. The name (usually a letter) is usually on a corner of the plane, in caps. We could see that there is an F on the bottom left hand corner of the plane, so F is our plane name.
To name an intersection of lines n and m, we have to find the point where they intersect and name it. We could see that point R goes through both lines, so that is our answer.
We have to name a point that does not contain lines l, m, or n. Point W is a point that is not on any of the lines.
Another name for line n is also line PS (add a line on the top of PS when writing this!) because point P and point S are two points on line n.
Line l does not intersect lines n or m because those lines do not go through line l at all.
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Given that ∠B ≅ ∠C.
to prove that the sides AB = AC
This can be done by the method of contradiction.
If possible let AB =AC
Then either AB>AC or AB<AC
Case i: If AB>AC, then by triangle axiom, Angle C > angle B.
But since angle C = angle B, we get AB cannot be greater than AC
Case ii: If AB<AC, then by triangle axiom, Angle C < angle B.
But since angle C = angle B, we get AB cannot be less than AC
Conclusion:
Since AB cannot be greater than AC nor less than AC, we have only one possibility. that is AB =AC
Hence if angle B = angle C it follows that
AB = AC, and AB ≅ AC.