Find the product and simplify your answer. 7a5(-3a⁴ + 5а - 5 )

Mathematics

1 answer:

Ad libitum [116K]3 years ago

7 0

Answer:

-21x^9+35x^6-35x^5

Step-by-step explanation:

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To obtain the area of a sector, what fraction is multiplied by the area of a circle (A = πr2)?

romanna [79]

Let r be a radius of a given circle and α be an angle, that corresponds to a sector.

The circle area is $A=\pi r^2$ and denote the sector area as $A_1$ .
Then $\dfrac{A_1}{A}= \dfrac{\alpha}{2\pi}$ (the ratio between area is the same as the ratio between coresponding angles).

$A_1=\dfrac{\alpha}{2\pi} \cdot A=\dfrac{\alpha}{2\pi} \cdot \pi r^2= \dfrac{r^2\alpha}{2}$ .

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3 years ago

What are two equivalent forms for 15xyz+10xy+5x

7nadin3 [17]

We can express this number in the standard form, which is simply 15xyz+10xy+5x. Alternatively, we can factor a 5 or an x out, receiving 5(3xyz+2xy+x) or x(15yz+10y+5). However, the most effective factorization is to factor out 5x, for a result of 5x(3yz+2y+1).

3 0

3 years ago

Pls help and thank youuuuu

Evgen [1.6K]

Answer:

$y=-2x+4$

Step-by-step explanation:

The gradient = change in y / change in x

When the x value increases by 1, the y value decreases by 2 so -2 / 1 = -2

The y intercept is 4, so it is +4

3 0

3 years ago

a yard is equal in length to three feet. the function F(y) takes a measurement in yards (as inputs) and returns a measurement in

Lina20 [59]

1 yard = 3 feet
F ( y ) = 3 y
F ( 10.5 ) = 3 yard * 10.5 feet / yard = 31.5 feet
Answer:
The output will be 31.5

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3 years ago

Read 2 more answers

nickel has an approximate diameter of 20 mm and an approximate thickness of 2 mm what is the approximate volume of a stack of 40

ziro4ka [17]

Answer:

The approximate volume of a stack of 40 nickels is 25132.741 cubic milimeters.

Step-by-step explanation:

A nickel can be modelled by the formula of a right cylinder, the approximate volume of the stack of nickels ( $V_{net}$ ), measured in cubic milimeters, is the product of the number of elements ( $n$ ), no unit, and the volume of each element ( $V$ ), measured in cubic milimeters. That is: