Solve the following equation: 156 + (7 – 3) x 7 = A. 174 B. 184 C. 1,050 D. 1,120

1 answer:

8 0

Using BEDMAS you follow the structure of what processes you need to do in the right mathematical order.

In this case, Brackets first, multiplication second, then adding.

Therefore answer he answer is C 184

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The water level in a tank can be modeled by the function h(t)=8cos(pi t /7)+11.5, where t is the number of

denis23 [38]

Answer:

NO amount of hour passed between two consecutive times when the water in the tank is at its maximum height

Step-by-step explanation:

Given the water tank level modelled by the function h(t)=8cos(pi t /7)+11.5. At maximum height, the velocity of the water tank is zero

Velocity is the change in distance with respect to time.

V = {d(h(t)}/dt = -8π/7sin(πt/7)

At maximum height, -8π/7sin(πt/7) = 0

-Sin(πt/7) = 0

sin(πt/7) = 0

Taking the arcsin of both sides

arcsin(sin(πt/7)) = arcsin0

πt/7 = 0

t = 0

This shows that NO hour passed between two consecutive times when the water in the tank is at its maximum height

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Answer:

LOP

Step-by-step explanation:

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No you can not simplify

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How much money should be invested at 5% interest, compounded quarterly, so that 7 years later the investment will be worth $5000

vampirchik [111]

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\to &\$5000\\
P=\textit{original amount deposited}\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, four times}
\end{array}\to &4\\
t=years\to &7
\end{cases}
\\\\\\
5000=P\left(1+\frac{0.05}{4}\right)^{4\cdot 7}\implies 5000=P(1.0125)^{28}\\\\\\ \cfrac{5000}{(1.0125)^{28}}=P$

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2 years ago