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cupoosta [38]
3 years ago
11

Multiple the following:

Mathematics
2 answers:
fredd [130]3 years ago
8 0

Answer:

1.-9x^2

2.16x^4

3.x^2+4x

4.x^2+4x+4

5.x^2-x-12

6.x^4+2x^3-4x^2

Step-by-step explanation:

Pepsi [2]3 years ago
8 0
1) (-3x)(3x)

= -9x^2

2) (4x)^2 = 4^2 x^2

= 16x^2

3) x(x+4) = x•x+4x

= x^2+4x

4) (x+2)^2 = x^2+2x•2+2^2

= x^2+4x+4

5) (x+3)(x-4) = x^2-4x+3x-12

= x^2-x-12

6) x^2(x^2+2x-4) = x^2•x^2•x^2•2x-4x^2

= x^4+2x^3-4x^2
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its f

Step-by-step explanation:

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Find the GCD (or HCF) of numerator and denominator

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normally distributed with mean 24.6 seconds and standard deviation 0.64 seconds;the lower finishing time, the better. If the qua
marshall27 [118]

Answer:

z=1.04

And if we solve for a we got

a=24.6 +1.04*0.64=25.27

So the value of height that separates the bottom 85% of data from the top 15% is 25.27.  

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the finishing time of a population, and for this case we know the distribution for X is given by:

X \sim N(24.6,0.64)  

Where \mu=24.6 and \sigma=0.64

Solution to the problem

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.15   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.85 of the area on the left and 0.15 of the area on the right it's z=1.04. On this case P(Z<1.04)=0.85 and P(z>1.04)=0.15

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P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.04

And if we solve for a we got

a=24.6 +1.04*0.64=25.27

So the value of height that separates the bottom 85% of data from the top 15% is 25.27.  

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