Find the measure of an exterior angle of a regular polygon with 18 sides.
1 answer:
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Move constant to the right-hand side and change its sign
2x^2 + 8 = -2 + 7
-2 + 7 = 5
Divide both sides of the equation by
x^2 + 4x = 5/2
Add (4/2^2) to both sides of the equation
x^2 + 4x + (4/2)^2 = 5/2 + (4/2)^2
factor the expression
(x + 4/2)^2 = 13/2
reduce the fraction by 2
(x + 2)^2 = 13/2
now solve equation for x
2x^2 + 8 = -2 + 7
-2 + 7 = 5
Divide both sides of the equation by
x^2 + 4x = 5/2
Add (4/2^2) to both sides of the equation
x^2 + 4x + (4/2)^2 = 5/2 + (4/2)^2
factor the expression
(x + 4/2)^2 = 13/2
reduce the fraction by 2
(x + 2)^2 = 13/2
now solve equation for x
change
given you
making x the subject by transferring the -19 to the right hand side of the equation
dividing through by 5
{}
also given
change the operation sign to =
dividing through by -4
so the truth set is
{x:x>9/4}.
The < sign changes to > because we divided by a negative number when solving for x