We have that the total students there are 500. The 12-graders there are 200. Probability is defined as the ratio of positive outcomes of an event, over all the possible outcomes. Suppose we pick student randomly. Then, there are 200 positive outcomes (positive outcome: we pick a student in 12th grade) and there are totally 500 outcomes (we can pick 500 students in total from Riverside High School). This ratio gives:
. The requested probability is 0.40
Answer:
a
Step-by-step explanation:
Answer:
(-3,-4)
Step-by-step explanation:
Note that the formula n(n+1)/2 is used only for adding n consecutive integers starting from 1.
A problem may not directly ask you for this but if you can break it down such that you have to find the sum of 'n consecutive integers starting from 1' then you can use this formula.
In the even integers questions, you may be required to find the sum of first 10 even integers.
2 + 4 + 6 + ... + 18 + 20
Take 2 common, 2*(1 + 2 + 3 + ...10)
To find the sum of the highlighted part, we can use the formula. Then we can multiply it by 2 to get the required sum.
Note that for odd integers, you cannot directly use this formula.
Sum the first 10 odd integers
1 + 3 + 5 + 7+...+19
But you can still make some modifications to find the sum.
1 + 3 + 5 + 7+...+19 = (1 +2+ 3 + 4+5 + 6+ 7+...+19 + 20) - (2 + 4+ 6+...20)
We know how to sum consecutive integers.
(1 +2+ 3 + 4+5 + 6+ 7+...+19 + 20) = 20*21/2
(2 + 4+ 6+...20) = 2 * (10*11)/2 = 10*11 (as before)
So 1 + 3 + 5 + 7+...+19 = (20*21/2) - (10*11) = 100
<span>The direct formula of sum of n consecutive odd integers starting from 1 = n^2 </span>
<span>_________________</span>
=<span> $17,000.00 + $17,000.00(1 + SUM[1.04]⁴) </span>
<span>= $17,000.00(1 + 4.41632256) </span>
<span>= $17,000.00(5.41632256) </span>
<span>= $92,077.48 </span>
<span>Answer: $92,077.48</span>