1² + 3² + 4² + 4(n - 1)² = ¹/₃n(2n - 1)(2n + 1)
1² + 3² + 4² + (2n - 2)² = ¹/₃n(2n - 1)(2n + 1)
1 + 9 + 16 + (2n - 2)(2n - 2) = ¹/₃n(2n(2n + 1) - 1(2n + 1))
10 + 16 + (2n(2n - 2) - 2(2n - 2)) = ¹/₃n(2n(2n) + 2n(1) - 1(2n) - 1(1) 16 + (2n(2n) - 2n(2) - 2(2n) + 2(2)) = ¹/₃n(4n² + 2n - 2n - 1)
26 + (4n² - 4n - 4n + 4) = ¹/₃n(4n² - 1)
26 + (4n² - 8n + 4) = ¹/₃n(4n² - 1)
26 + 4n² - 8n + 4 = ¹/₃n(4n²) - ¹/₃n(1)
4n² - 8n + 4 + 26 = 1¹/₃n³ - ¹/₃n
4n² - 8n + 30 = 1¹/₃n³ - ¹/₃n
+ ¹/₃n + ¹/₃n
4n² - 7²/₃n + 30 = 1¹/₃n³
-1¹/₃n³ + 4n² - 7²/₃n + 30 = 0
-3(-1¹/₃n³ + 4n² - 7²/₃n + 30) = -3(0)
-3(-1¹/₃n³) - 3(4n²) - 3(-7²/₃n) - 3(30) = 0
4n³ - 12n² + 23n - 90 = 0
For this case we must make a conversion from pounds to kilograms.
By definition we have to:
1 kg equals 2.20462 pounds. Making a rule of three we have:
2.20462 pounds ---------------> 1 kg
127 pounds -----------------------> x
Where "x" represents the amount of kg.

Thus, 127 pounds represent 57.61 kilograms.
Answer:
57.61 kilograms.
Answer:
see explanation
Step-by-step explanation:
Given
3x² - 5x + 2 = 0
Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term
product = 3 × 2 = 6 and sum = - 5
The factors are - 3 and - 2
Use these factors to split the x- term
3x² - 3x - 2x + 2 = 0 ( factor the first/second and third/fourth terms )
3x(x - 1) - 2(x - 1) = 0 ← factor out (x - 1) from each term
(x - 1)(3x - 2) = 0
Equate each factor to zero and solve for x
x - 1 = 0 ⇒ x = 1
3x - 2 = 0 ⇒ 3x = 2 ⇒ x = 
Roots are x = 1, x = 