To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
Answer:
a = 22
b = 31
c = 13
Step-by-step explanation:
The sum is the same in each row, column, and diagonal.
One of the diagonals is already complete. The sum is:
16 + 25 + 34 = 75
So the first row adds up to 75:
a + 37 + 16 = 75
a = 22
The second row adds up to 75:
19 + 25 + b = 75
b = 31
And the third row adds up to 75:
34 + c + 28 = 75
c = 13
We can check our answer by finding the sum of each column and the other diagonal.
22 + 19 + 34 = 75
37 + 25 + 13 = 75
16 + 31 + 28 = 75
22 + 25 + 28 = 75
A: High School P, because it has the lowest <span>σ
B: High School N, because it has the highest mean</span>
Answer:
The correct answer is y = 20x.
Step-by-step explanation:
