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3 years ago

13

"the distribution of means is the correct comparison distribution when"

1 answer:

alexandr402 [8]3 years ago

4 0

The distribution of means is the correct comparison distribution when

Answer: The distribution of means is the correct comparison distribution when there is more than one person in a sample.

The distribution of the sample means is also called the sampling distribution of mean. It is most appropriate when we take a random sample of size n from the population of size N. The distribution of the sample means will follow normal distribution with mean = $\mu$ and standard deviation = $\frac{\sigma}{\sqrt{n}}$

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13) Circle O is shown with point A, B, C, and D on Circle O.

sladkih [1.3K]

The value of y is 50

The angle measurement of angle AOB is 100°

<h3>Circle Geometry </h3>

From the question, we are to determine the value of y and the measure of angle AOB

From one the circle theorems, we have that

Angles in the <u>same segment</u> are equal

In the given diagram, x° and y° are angles in the same segment

∴ x° = y°

From the given information,

x = 50

∴ y = 50

Hence, the value of y is 50

Also, from another circle theorem,

Angle at the <u>center</u> is twice the angle at the <u>circumference</u>

∴ ∠AOB = 2x° = 2y°

Then,

∠AOB = 2×50°

∠AOB = 100°

Hence, the angle measurement of angle AOB is 100°

Learn more on Circle Geometry here: brainly.com/question/17074363

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7 0

1 year ago

Ahmed is making 8 kites. He uses 5 yards of ribbon for each kite. If he adds 3 more identical kites which he has already made be

il63 [147K]

he would have 11 kites in total, hope this helps!

3 0

2 years ago

Consider the given matrix. 1 −1 0 5 1 4 0 1 1 Find the eigenvalues. (Enter your answers as a comma-separated list.) λ = Find the

fomenos

Answer:

Step-by-step explanation:

We have to diagonalize the matrix

$\left[\begin{array}{ccc}1&-1&0\\5&1&4\\0&1&1\end{array}\right]$

we have to solve the expression

$|A-\lambda I|=0$

Thus, by applying the determinant we obtain the polynomial

$(1-\lambda )^3+5-4=0\\(1-\lambda )^3+1=0\\$

$-\lambda^3+3\lambda^2-4\lambda+2$

$\lambda_1=1\\\lambda_2=1-i\\\lambda_3=1+i\\$

and the eigenvector will be

$v_1=(-4,0,5)\\v_2=(-1,-i,-1)\\v_3=(-1,i,1)$

HOPE THIS HELPS!!

3 0

3 years ago

PLEASE HELP!!!!!!!

Ilya [14]

It’s reflected over A

6 0

2 years ago

Read 2 more answers

Find the missing angel by using an equation

Marina CMI [18]

Lets x = missing angle

x = 180 - (60+80)
x = 180 - 140
x = 40

answer
40

6 0

3 years ago