I NEED HELP WITH THIS ASAP!!! FOR BRAINLIEST LASTQ
2 answers:
Answer: A
Step-by-step explanation:
For this problem, we know that A is the correct answer. A is the same as the given expression because it is the same, but the order is switched. When you multiply both of them, you would get the same answer.
We can eliminate B because should be positive, not negative.
We can eliminate C because the fraction should be , not
.
We can eliminate D because (-1×-7) given you 7, not -7.
Therefore, A is the right answer.
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one way would be to factor
I can't factor it so we will have to use Descartes' Rule of Signs which is helpful for finding how many real roots you have
it goes like this:
for a polynomial with real coefients, consider .
after arranging the terms in decending order in terms of degree, count how many times the signs of the coeffients change direction and minus 2 from that number until you get to 1 or 0. that will be the number of even roots the function can have
We have (-, -, +, +). the signs changed 1 times, so it has 1 real positive root
to get the negative roots, we evaluate f(-x) and see how many times the root changes
signs are (-, -, -, +). there was 1 change in sign
so the function has 1 real negative root
a total of 2 real roots
a function of degree can have at most,
roots
our function is degree 6 so it has 6 roots
if 2 are real, then the others must be complex
6-2=4 so there are 4 complex roots
you can also show that there are only 2 real roots by using a graphing utility to see that there are only 2 real roots