Give at least examples where an object has multiple motions.
1 answer:
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Answer:
Tamara should expect the sum of the two cubes to be equal to 5 20 times.
Step-by-step explanation:
The sample space of rolling a number cube are:
S = {1, 2, 3, 4, 5, 6}
If two such cubes are rolled together, then the sum of the two cubes will be 5 for the combinations below:
S₁ = {(1, 4), (2, 3), (3, 2) and (4, 1)}
The total number of outcomes will be, <em>N</em> = 36.
Compute the probability that the sum of rolling two numbered cubes as follows:
Let <em>X</em> = number of time the sum of the two numbers on two cubes is 5.
Two numbered cubes are rolled <em>n</em> = 180 times.
The event of getting a sum of 5 in independent of the other results.
The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 180 and <em>p</em> = .
The expected value of <em>X</em> is:
Compute the expected number of times Tamara expects the sum of the two cubes to be equal to 5 as follow:
Thus, Tamara should expect the sum of the two cubes to be equal to 5 20 times.
Answer:
- See attachment for table values
- y₁ = y₂ for x = 6
Step-by-step explanation:
In each case, put the x-value in the formula and do the arithmetic. If you're allowed, you can save some time and effort by realizing that the solution (x) will have to be an even number.
y₁ is an integer value for all integer values of x. y₂ is an integer value for even values of x only. y₁ and y₂ will both be integers (and possibly equal) only when x is even.
For example, for x = 6, we have
... y₁ = 3·6 - 8 = 18 -8 = 10
... y₂ = 0.5·6 +7 = 3 +7 = 10
That is, for x = 6, both columns of the table have the same number (10). That is, y₁ = y₂ for x = 6. The solution to the equation
... y₁ = y₂
is
... x = 6.
