The function of the object height is an illustration of a projectile motion
The object will never hit the ground
<h3>How to determine when the object hits the ground?</h3>
The function is given as:
h=16t^2+80t+96.
When the object hits the ground, h = 0
So, we have:
16t^2+80t+96 = 0
Divide through by 16
t^2+5t+6 = 0
Expand
t^2 + 3t + 2t + 6 = 0
Factorize
t(t + 3) + 2(t + 3) = 0
Factor out t + 3
(t + 2)(t + 3) = 0
Solve for t
t = -2 or t = -3
The time (t) cannot be negative.
Hence, the object will never hit the ground
Read more about projectile motion at:
brainly.com/question/1130127
Midsegment = 1/2(base1 + base2)
EF = 1/2(AB + CD)
EF = 1/2(20 + 12)
EF = 1/2(32)
EF = 16
Answer
EF = 16
So all your doing is plotting the points, for example find 0 then count forward twice- u will plot and label it their. Its the same process for each number. (ps if its negative go backwards)
I believe that the snail would be 43 5/12 inches away from the bottom after 20 minutes.
