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3 years ago

7

How are tax and discount the same?

2 answers:

Yuri [45]3 years ago

8 0

Tax is different than discount.

Tax is an amount added, while discount is an amount subtracted from total.

Bogdan [553]3 years ago

4 0

Tax adds money and discount takes away so both of them has to deal with money

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A cat has a litter of 7 kittens. find the probability that exactly 5 of the little furballs (kittens) are female. assume that ma

zvonat [6]

The probability 0.1641.

The binomial distribution is

$_nC_r(p)^r(1-p)^{n-r}$

For this problem, we have:
$_7C_5(0.5)^5(1-0.5)^{7-5}
\\
\\=\frac{7!}{5!2!}(0.5^5)(0.5)^2=0.1641$

4 0

3 years ago

9. Combine the radical expression, if possible.

Anastaziya [24]

Answer:

we conclude that:

$3\sqrt{125}+4\sqrt{20}=23\sqrt{5}$

Hence, the last option i.e. $23\sqrt{5}$ is correct.

Step-by-step explanation:

Given the expression

$3\sqrt{125}+4\sqrt{20}$

Combining the radical expressions

$3\sqrt{125}+4\sqrt{20}$

let us first solve

$3\sqrt{125}$

$=3\sqrt{5^3}$

$=3\sqrt{5^2\cdot \:5}$

Apply radical rule: $\sqrt{ab}=\sqrt{a}\sqrt{b},\:\quad \:a\ge 0,\:b\ge 0$

$=3\sqrt{5^2}\sqrt{5}$

Apply radical rule: $\sqrt{a^2}=a,\:\quad \:a\ge 0$

$=3\cdot \:5\sqrt{5}$

$=15\sqrt{5}$

Thus,

$3\sqrt{125}=15\sqrt{5}$

similarly solving

$4\sqrt{20}$

$=4\sqrt{2^2\cdot \:5}$

Apply radical rule: $\sqrt{ab}=\sqrt{a}\sqrt{b},\:\quad \:a\ge 0,\:b\ge 0$

$=4\sqrt{2^2}\sqrt{5}$

Apply radical rule: $\sqrt{a^2}=a,\:\quad \:a\ge 0$

$=4\cdot \:2\sqrt{5}$

$=8\sqrt{5}$

Thus,

$4\sqrt{20}=8\sqrt{5}$

so we get

$3\sqrt{125}=15\sqrt{5}$

$4\sqrt{20}=8\sqrt{5}$

so the expression becomes

$3\sqrt{125}+4\sqrt{20}=15\sqrt{5}+8\sqrt{5}$ ∵ $3\sqrt{125}=15\sqrt{5}$ , $4\sqrt{20}=8\sqrt{5}$

$=23\sqrt{5}$ ∵ $15\sqrt{5}+8\sqrt{5}=23\sqrt{5}$

Therefore, we conclude that:

$3\sqrt{125}+4\sqrt{20}=23\sqrt{5}$

Hence, the last option i.e. $23\sqrt{5}$ is correct.

7 0

3 years ago

Write in standard form<br> - x + 2.5+(-4.1)

Marianna [84]

Answer: =-x-1.6

Step-by-step explanation: Using the formula, write in standard form.

Hope this helps you out.

5 0

3 years ago

Based on a random sample of 25 units of product X, the average weight is 102 lbs., and the sample standard deviation is 10 lbs.

Alex

Answer:

Step-by-step explanation:

Given that for a sample size of 25, sample mean = 102 lbs. and sample std deviation = 10 lbs.

$H_0: \bar x = 100\\H_a: \bar x >100$

(Right tailed test)

Given that we assume population is normally distributed

Test statistic:

Mean difference = +2

Std error of sample = $\frac{10}{\sqrt{25} } =2$

t = test statistic = Mean diff/Std error $= 1$

degree of freedom $= n-1 =24$

Critical value of t = 1.711

Our test statistic >1.71

Accept alternate hypothesis

Because there is significant difference between the test statistic and test statistic lies above critical value.

3 0

3 years ago

Solve the following equation by completing the next two lines (showing all work )<br> X + 6 = 10

WITCHER [35]

Answer:

x=10-6

x=4

Step-by-step explanation:

for which level

6 0

3 years ago