Four friends each bought a movie ticket and two boxes of candy at a movie theater. The tickets were $ 7.50 and the boxes of cand

Question

jok3333 [9.3K]

4 years ago

14

Four friends each bought a movie ticket and two boxes of candy at a movie theater. The tickets were $ 7.50 and the boxes of cand

y cost the same amount. If the total cost for all four friends was $ 58.00, what was the price of one (1) box of candy.

Mathematics

2 answers:

777dan777 [17] · Answer 1 · 2021-12-19T11:34:22+03:00

777dan777 [17]4 years ago

6 0

Subtract the cost of tickets from the total. 4x7.5=30. 58-30=28. Eight boxes of candy were purchased in total. Use c to represent candy. 8c=28. Finally, divide both by 8. 28/8= 3.5. The answer is $3.50.

Oksana_A [137] · Answer 2 · 2021-12-19T12:48:01+03:00

Oksana_A [137]4 years ago

4 0

Answer:

$7

Step-by-step explanation:

58-7.50x4=30 58-30=28/4=7