Answer:
v₀ = 14.6 m / s
Explanation:
This is a projectile launch exercise, in this case we must stop the wall, we can assume that at this point the ball is at its maximum height
as the height is maximum its vertical speed is zero
v_{y} = - g t
y = v_{oy} t - ½ g t²
the horizontal distance is
x = v₀ₓ t
we use trigonometry to find the components of the velocity
sin θ = v_{oy} / v₀
cos θ = v₀ₓ / v₀
v₀ₓ = v₀ cos θ
v_{oy} = v_{o} sin θ
we substitute the values
0 = v₀ sin θ - g t
10 = v₀ sin θ t - ½ g t²
6 = v₀ cos θ t
we have three equations and three unknowns by which the system can be solved
let's use the first and second equations,
10 = (gt) t - ½ g t²
10 = g t² - ½ g t²
10 / 9.8 = t² (1- ½)
1.02 = ½ t²
t = √ 2.04
t = 1,429 s
this is the time to hit the wall
now let's use the first and third equations, we substitute the data
v₀ sin θ = g t
v₀ cos θ = x / t
we divide and simplify
tan θ = g t² / x
θ = tan⁻¹ g t² / x
θ = tan⁻¹ (9.8 1.429²/6)
θ = 73.3°
we substitute in the third equation
x = v₀ cos 73.3 t
v₀ = x / t cos 73.3
v₀ = 6 / (1.429 cos 73.3)
v₀ = 14.6 m / s
Helium because it has 2/2 electrons already
Answer:
my name is Deepika Pandey anion I am 9 years old my father name is Dinesh Pandey my name is and my sister name is sister name is a
Answer:
(a) Velocity will be 17.146 m/sec
(b) Volume flow rate will be
Explanation:
We have given height of the dam h = 15 m
Acceleration due to gravity
Effective area
(a) From conservation of energy
Potential energy at the top will be equal to kinetic energy at the bottom
So
(b) We have to find the volume flow rate
Volume flow rate is given by