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4 years ago

What are the mean, median, and mode of the following data set?

Mathematics

1 answer:

sveta [45]4 years ago

3 0

Answer:

C- mean: 9/20, median: 2/5, mode: 3/4

Step-by-step explanation:

I used process of elimination so it only took a minute, rather than adding all of them up and finding a common denominator.

3/4 shows up twice while the rest show up once, its obviously the mode.

if you put them in order:

1/10 , 1/4 , 2/5, 3/4 , 3/4

you have 2/5 in the middle.

(And if you want to do the whole thing, an easier way to find the mean is changing them to decimals (.1, .25, .4, .75, .75) and changing them back to fractions once you have the answer is an easier way of doing it.

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Complete the table for this equation. y=x+6

weeeeeb [17]

Answer:

Step-by-step explanation:

4 0

2 years ago

. Lightning Strikes It has been said that the probability of being struck by lightning is about 1 in 750,000, but under what cir

mrs_skeptik [129]

Complete Question

The complete question is shown on the first uploaded image

Answer:

$P(U |D ) = 0.198$

$P(O\ n \ B) = 0.188$

$P(O | B) = 0.498$

Step-by-step explanation:

The total number of deaths is mathematically represented as

$T = 16 + 23 + \cdots + 16$

$T =623$

The total number of deaths in 1996 - 2000 is mathematically represented as

$T_a = 16 + 23+ \cdots + 30$

$T_a = 235$

The total number of deaths in 2001 - 2005 is mathematically represented as

$T_b = 17 + 16 + \cdots + 23$

$T_b = 206$

The total number of deaths in 2006 - 2010 is mathematically represented as

$T_c = 15 + 17 + \cdots + 16$

$T_d = 182$

Generally the the probability that it would occur under the tree given that the death was after 2000 is mathematically represented as

$P(U |D ) = \frac{P(A \ n\ U )}{P(A)}$

Here $P(A \ n\ U )$ represents the probability that it was after 2000 and it was under the tree and this is mathematically represented as

$P(A \ n\ U ) = \frac{Z}{ T}$

Here Z is the total number of death under the tree after 2000 and it is mathematically represented as

$Z = 35 + 42$

=> $Z = 77$

=> $P(A \ n\ U ) = \frac{77}{ 623}$

Also

$P(A)$ is the probability of the death occurring after 2000 and this is mathematically represented as

$P(A) = \frac{T_b + T_c}{ T}$

=> $P(A) = \frac{ 206+ 182}{623}$

$P(U |D ) = \frac{\frac{77}{ 623} }{ \frac{ 206+ 182}{623}}$

=> $P(U |D ) = 0.198$

Generally the probability that the death was from camping or being outside and was before 2001 is mathematically represented as

$P(O | B) = \frac{T_z}{ T}$

Here $T_z$ is the total number of death outside / camping before 2001 and the value is 117

$P(O \ n \ B) = \frac{117}{623}$

=> $P(O\ n \ B) = 0.188$

Generally the probability that the death was from camping or being outside given that it was before 2001 is mathematically represented as

$P(O | B) = \frac{ P( O \ n \ B)}{ P(B)}$

Here $P(B)$ is the probability that it was before 2001 , this is mathematically represented as

$P(B ) = \frac{T_a}{T}$

=> $P(B ) = \frac{235}{623}$

$P(O | B) = \frac{ \frac{117}{623}}{ \frac{235}{623}}$

=> $P(O | B) = 0.498$

5 0

3 years ago

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jekas [21]

Answer:

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3 years ago

On a coordinate plane, what is the distance between the points (3,-6) and (-14, -6)

madreJ [45]

Answer:

The distance between both points would be of 17 units

Step-by-step explanation:

they have the same value through the y-axis. However if you count the spots from 3 to -14 their x values are 17 units apart.

7 0

3 years ago

Carmen currently has $5; she makes $2 a week in allowance. Question: a) Write a function C(x) that represents how much money she

aivan3 [116]

For question a) you can do 2 x 7 sine their are 7 days in a week 2 x 7 = 19 so by the end of each week Carmen has $19. in 10 weeks she will have $20 dollars. if in 10 weeks she has $20 wait if it is time two there can't be 35 try 17 cause that's closes so in 17 she will have $36. Same thing Lilly starts with $10 each week she gets $1 a week so 1 x 7 = 7 and since she started with $ 10 she has $17 Lilly must earn 19 dollars to be equal with Carmen. Hope this helps

6 0

3 years ago

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