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rosijanka [135]
3 years ago
11

Twenty-four players divided into three teams?

Mathematics
2 answers:
avanturin [10]3 years ago
8 0
24÷3=8

There will be eight players on each team.
Korvikt [17]3 years ago
4 0
Twenty four divided by 3 is eight so there would be 8 players on each team
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What is the vertex of this function f(x)=x^2+12x
tankabanditka [31]

Answer:

(-6, 36)

Step-by-step explanation:

The standard form: ax^2 + bx + c

In this case:

a is 1

b is 12

c is 0

Calculate -b / 2a. This is the x-coordinate of the vertex.

To find the y-coordinate of the vertex, simply plug the value of -b / 2a into the equation for x and solve for y. This is the y-coordinate of the vertex.

-12 / ( 2 x 1 )

-12 / 2

-6

You log -6 in the function

f(x) = x^2 + 12x

f(-6) = (-6)^2 + 12(-6)

      = 36 +  (-72)

      = 36 - 72

      = 36

I hope this

4 0
3 years ago
A school has a parking lot that is 150.23 feet by 135.12 feet. What is the perimeter of the parking lot?
elena-14-01-66 [18.8K]

Answer: 570.70 ft

Step-by-step explanation:

The perimeter is the distance around the entire parking lot.

The measurement of 150.23 ft by 135.12 ft is half of the distance of the lot because it represents just two sides yet there are 4 sides.

The other two sides have the same measurement as this is a rectangle.

The perimeter of the parking lot is:

= (150.23 * 2) + (135.12 * 2)

= 570.70 ft

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3 years ago
3.2 x 10^5<br> Convert to standard form
Harman [31]

Answer

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4 0
3 years ago
Read 2 more answers
If f(x) = 3x^2 - 4x + 5 and g(x) = 2x^2 + 2,<br> find f(x) – g(x).<br><br> Answer: x^2 - 4x + 3
Nadusha1986 [10]

Answer:

f(x) – g(x) = x^2 - 4x + 3

Step-by-step explanation:

f(x) = 3x^2 - 4x + 5 and g(x) = 2x^2 + 2,

f(x) – g(x) = 3x^2 - 4x + 5 - ( 2x^2 + 2)

Distribute the minus sign

f(x) – g(x) = 3x^2 - 4x + 5 - 2x^2 - 2

  Combine like terms

f(x) – g(x) = x^2 - 4x + 3

 

5 0
3 years ago
Use &lt;, &gt;, or = to compare the following decimals 4.06 4.4 0.50 0.5 5.99 9.21
Gnesinka [82]

Answer:

9.21>5.99>.5=.50>4.4>4.06

4 0
3 years ago
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