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Serga [27]
3 years ago
14

What is the value of the digit 7 in the number 475

Mathematics
2 answers:
faltersainse [42]3 years ago
5 0
The value of the digit 7 in the number 475 is the Tens place. 

Good Luck! :)
andrew11 [14]3 years ago
3 0
It is in the tens place, so the digit's value is 70.
Hope that helped you.
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Please help will give brainliest and 80 points
belka [17]

Answer:

Start

A2

B2

B1

C1

C2

D2

D3

D4

C4

END

Step-by-step explanation:

Start (A3)

x is equal to 141 because they are alternate interior angles.

A2. x is equal to 39 because they are corresponding angles.

B2. x would be supplementary to 41 because the angle that x supplements is corresponding to 41.

41 + x = 180 due to the linear pair postulate. Therefore, x = 139.

B1. x would be supplementary to 82 because they are consecutive exterior angles.

82 + x = 180 due to the linear pair postulate. Therefore, x = 98.

C1. x = 102 due to the vertical angles theorem.

C2. x would be supplementary to 130 because the angle that x supplements is equal to 130 (Alternate Exterior Angles).

130 + x = 180, x = 50.

D2. x = 74, corresponding angles.

D3. x = 83, corresponding angles.

D4. x = 95, corresponding

C4. x is supplementary to 18 because of the consecutive interior angles theorem.

x = 162

END

8 0
3 years ago
Read 2 more answers
Kelly uses a building block to create the top of a tower. The front face of the building block is shown.
max2010maxim [7]
What you need to do is do the formula of Area=1/2×Height (Base B +Base A) Base B is bottom Base A is the top then you divide by 2 In this case 1/2 ×8/1 ×(12+15)=108
3 0
3 years ago
What is 3x+6y=16. what do i do please help
DochEvi [55]
Ok, so for this you're likely graphing in y=mx+b format (slope intercept). So to start, you'all first subtract 3x from the equation to get 6y=-3x+16. Now you'll divide the equation by 6 to get y alone. Your final equation will be y=-1/2x+16/6
7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B5x%2F8y%7D" id="TexFormula1" title="\sqrt[4]{5x/8y}" alt="\sqrt[4]{5x/8y}" al
Furkat [3]

Answer:  \frac{\sqrt[4]{10xy^3}}{2y}

where y is positive.

The 2y in the denominator is not inside the fourth root

==================================================

Work Shown:

\sqrt[4]{\frac{5x}{8y}}\\\\\\\sqrt[4]{\frac{5x*2y^3}{8y*2y^3}}\ \ \text{.... multiply top and bottom by } 2y^3\\\\\\\sqrt[4]{\frac{10xy^3}{16y^4}}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{16y^4}} \ \ \text{ ... break up the fourth root}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{(2y)^4}} \ \ \text{ ... rewrite } 16y^4 \text{ as } (2y)^4\\\\\\\frac{\sqrt[4]{10xy^3}}{2y} \ \ \text{... where y is positive}\\\\\\

The idea is to get something of the form a^4 in the denominator. In this case, a = 2y

To be able to reach the 16y^4, your teacher gave the hint to multiply top and bottom by 2y^3

For more examples, search out "rationalizing the denominator".

Keep in mind that \sqrt[4]{(2y)^4} = 2y only works if y isn't negative.

If y could be negative, then we'd have to say \sqrt[4]{(2y)^4} = |2y|. The absolute value bars ensure the result is never negative.

Furthermore, to avoid dividing by zero, we can't have y = 0. So all of this works as long as y > 0.

3 0
3 years ago
I don't get this I need help?
Aleks04 [339]

Answer: 4r^2

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
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