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3 years ago

Please answer this question with explanation!! Thanks

Mathematics

1 answer:

Georgia [21]3 years ago

5 0

The answer would be 12 3/4 because when you continue use the pattern that is used you end up with your answer! Hope this helps

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Please help :) Thank you

Anni [7]

Answer:

Explanation:

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3 0

3 years ago

If f(x) and f^-1(x) are inverse functions of each other and f(x)=2x+5, what is f^-1(8)

BARSIC [14]

I hope this helps you

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2 years ago

Read 2 more answers

Forty minutes of hot yoga and 10 minutes of jumping jacks burns 510 calories. Thirty minutes at hot yoga and 20 minutes of jumpi

son4ous [18]

Answer:

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Step-by-step explanation:

ur answer I have the link

8 0

2 years ago

How do you solve these equations? I don't want you to answer all of them, just tell me how to solve each type of equation on the

miss Akunina [59]

Answer:

8. Identify the common denominator; express each fraction using that denominator; combine the numerators of those rewritten fractions and express the result over the common denominator. Factor out any common factors from numerator and denominator in your result. (It's exactly the same set of instructions that apply for completely numerical fractions.)

9. As with numerical fractions, multiply the numerator by the inverse of the denominator; cancel common factors from numerator and denominator.

10. The method often recommended is to multiply the equation by a common denominator to eliminate the fractions. Then solve in the usual way. Check all answers. If one of the answers makes your multiplier (common denominator) be zero, it is extraneous. (10a cannot have extraneous solutions; 10b might)

Step-by-step explanation:

For a couple of these, it is helpful to remember that (a-b) = -(b-a).

$\dfrac{5}{x+2}+\dfrac{25-x}{x^2-3x-10}=\dfrac{5(x-5)}{(x+2)(x-5)}+\dfrac{25-x}{(x+2)(x-5)}\\\\=\dfrac{5x-25+25-x}{(x+2)(x-5)}=\dfrac{4x}{x^2-3x-10}$

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$\displaystyle\frac{\left(\frac{x}{x-2}\right)}{\left(\frac{2x}{2-x}\right)}=\frac{x}{x-2}\cdot\frac{-(x-2)}{2x}=\frac{-x(x-2)}{2x(x-2)}=-\frac{1}{2}$

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$\dfrac{3}{x-1}+\dfrac{6}{x^2-3x+2}=2\\\\\dfrac{3(x-2)}{(x-1)(x-2)}+\dfrac{6}{(x-1)(x-2)}=\dfrac{2(x-1)(x-2)}{(x-1)(x-2)}\\\\3x-6+6=2(x^2-3x+2) \qquad\text{multiply by the denominator}\\\\2x^2-9x+4=0 \qquad\text{subtract 3x}\\\\(2x-1)(x-4)=0 \qquad\text{factor; x=1/2, x=4}$

Neither solution makes any denominator be zero, so both are good solutions.

8 0

3 years ago

What is 2/5 divided 3/4

Zepler [3.9K]

Answer:

8/15

Step-by-step explanation:

To divide by a fraction, change the division to a multiplication, and flip the fraction.

2/5 / 3/4 = 2/5 * 4/3 = 8/15

4 0

3 years ago