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2 years ago

11

A cookie recipe calls for 3/4 cup of sugar.if Mrs mcComas has four and a half cups of sugar left, how many batches of cookie can

she bake?

1 answer:

matrenka [14]2 years ago

8 0

Answer: 6

Step-by-step explanation: 4 1/2=4 2/4. 4 2/4 divided by 3/4 equals 6

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For every 2 gallons of vanilla ice cream a shop sells, they sell 11 gallons of chocolate ice cream. If they sell 16 gallons of v

Novay_Z [31]

Answer: 88 gallons

Step-by-step explanation:

Every 2 vanillas = 11 chocolates

so 16 vanillas = 88 chocolates

i did this by multiplying both numbers by 8

sorry if this is wrong

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3 years ago

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- Javid bought 3 pairs of Nike Jordan True Flight sneakers

Tanya [424]

Answer:

a b c or d is the answer

Step-by-step explanation:

no explanation

8 0

2 years ago

Find the general expression for the slope of a line tangent to the curve of y=2x^2+4x at the point P(x,y) . Then find the slopes

ArbitrLikvidat [17]

Complete Question

Find the general expression for the slope of a line tangent to the curve of y=2x^2+4x at the point P(x,y) . Then find the slopes for $x = 3$ and x=0.5. Sketch the curve and the tangent lines. What is the general expression for the slope of a line tangent to the curve of the function y=2x^2+4 at the point P(x,y) ?

Answer:

The generally expression for the slope of $y = 2x^2 + 4x$ is $y' = 4x +4$

The graph is shown on the first uploaded image

The generally expression for the slope of $y=2x^2+4$ is $y' = 4x$

Step-by-step explanation:

From the question we are told that

The equation of the curve is $y = 2x^2 + 4x$

First we differentiate the equation

So

$y' = 4x +4$

Therefore the generally expression for the slope tangent to the curve $y=2x^2+4x$ is $y' = 4x +4$

The next step is to substitute for x = 3 and x = 0.5

So for $x_1 = 3$

$y' = 4(3) +4$

$y' =m_1= 16$

And for $x_2 = 0.5$

$y' = 4(0.5) +4$

$y' =m_2= 6$

Here m_1 and m_2 are slops of the curve

Next we obtain the coordinates of the tangent lines

So at $x_1 = 3$

$y_1 = 2(3)^2 + 4(3)$

$y_1 = 21$

So the coordinate for the first tangent line is

$(x_1 , y_1 ) = (3 , 21)$

At $x_2 = 0.5$

$y_2 = 2(0.5)^2 + 4(0.5)$

=> $y_2 = 2.5$

So the coordinate for the second tangent line is

$(x_2 , y_2 ) = (0.5 , 2.5)$

Next we obtain the equation for the tangent lines

So generally the slope is mathematically represented as

$m = \frac{y - y_1 }{x-x_1}$

For $(x_1 , y_1 ) = (-3 , 21)$ and $y' =m_1= 16$

$16 = \frac{y -21 }{x-3)}$

=> $y = 16x - 27$

For $(x_2 , y_2 ) = (0.5 , 2.5)$ and $y' =m_2= 6$

$6 = \frac{y -2.5 }{x-0.5}$

$y = 6x -0.5$

Generally the general expression for the slope of a line tangent to the curve of the function y=2x^2+4 at the point P(x,y) is mathematically evaluated by differentiating y=2x^2+4 as follows

$y' = 4x$

7 0

3 years ago

SOLVE. integration of (1-v) /(1+v^2)

Nutka1998 [239]

$\displaystyle\int\frac{1-v}{1+v^2}\,\mathrm dv=\int\frac{\mathrm dv}{1+v^2}-\int\frac v{1+v^2}\,\mathrm dv$

The first integral is already standard and has an antiderivative in terms of $\arctan v$ . For the second integral, take $w=1+v^2$ so that $\dfrac{\mathrm dw}2=v\,\mathrm dv$ . Then

$\displaystyle\int\frac{\mathrm dv}{1+v^2}-\int\frac v{1+v^2}\,\mathrm dv=\arctan v-\frac12\int\frac{\mathrm dw}w$
$=\arctan v-\dfrac12\ln|w|+C$
$=\arctan v-\dfrac12\ln(1+v^2)+C$

4 0

3 years ago

whats an rational and a irrational number between 1.4 and 1.6. include the decimal approximation of the irrational number to the

Liono4ka [1.6K]

1.5 is a rational number because it can be written as a fraction.
1.56 or 1.555555 repeating is not a rational number.

7 0

3 years ago

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