All categories

1 year ago

ASAP PLS I NEED IT AND TY

Mathematics

2 answers:

mars1129 [50]1 year ago

8 0

<h2>Dilations and Scale Factors</h2>

When we're solving with scale factors, we either divide or multiply.

If the shape becomes larger, we multiply to get the new length.

If the shape becomes smaller, we divide to get the new length.

<h2>Solving the Question</h2>

We're given:

Original side length is 2.5 units
Scale factor = 6

Because the shape becomes larger, we have to multiply the original side length by the scale factor, 6, to get the new side length.

2.5 x 6 = 15

Therefore, the missing side length is 15 units.

<h2>Answer</h2>

15 units

jeka57 [31]1 year ago

7 0

Answer:

Step-by-step explanation:

You might be interested in

3 divided by 5 (step by step)<br><br>

snow_lady [41]

0. 6 0 0
5 3. 0 0 0
− 0
3 0
− 3 0
0 0
− 0
0 0
− 0
0

6 0

2 years ago

Marilyn has 7/8 yard of ribbon. What is the maximum number of 1/16 yard-long pieces Marilyn can cut from this ribbon?

makkiz [27]

Marilyn can cut 14 pieces

6 0

3 years ago

Ms. Skeen bought 3 pounds of candy for the Christmas party. There was a total of 147 pieces of candy. She wants to divide it amo

ohaa [14]

The 3 lbs of candy is irrelevant, so we can discard that. All you need to do is divide 147 by 26, which is 5.65 pieces of candy. Each student will get 5 pieces, with a few left over.

5 0

2 years ago

HEEELP ME GEOMETRY HW #29 AND #30 I'VE BEEN STUCK ON IT FOR HOURS!!!!!

natulia [17]

On #29 x = 12 and <apb = 90° and <dcb = 40° and on #30 all I dont even understand, sorry

5 0

3 years ago

The heights of a certain type of tree are approximately normally distributed with a mean height p = 5 ft and a standard

arsen [322]

Answer:

A tree with a height of 6.2 ft is 3 standard deviations above the mean

Step-by-step explanation:

⇒ $1^s^t$ statement: A tree with a height of 5.4 ft is 1 standard deviation below the mean(FALSE)

an X value is found Z standard deviations from the mean mu if:

$\frac{X-\mu}{\sigma} = Z$

In this case we have: $\mu=5\ ft$ $\sigma=0.4\ ft$

We have four different values of X and we must calculate the Z-score for each

For X =5.4\ ft

$Z=\frac{X-\mu}{\sigma}\\Z=\frac{5.4-5}{0.4}=1$

Therefore, A tree with a height of 5.4 ft is 1 standard deviation above the mean.

⇒ $2^n^d$ statement:A tree with a height of 4.6 ft is 1 standard deviation above the mean. (FALSE)

For X =4.6 ft

$Z=\frac{X-\mu}{\sigma}\\Z=\frac{4.6-5}{0.4}=-1$

Therefore, a tree with a height of 4.6 ft is 1 standard deviation below the mean .

⇒ $3^r^d$ statement:A tree with a height of 5.8 ft is 2.5 standard deviations above the mean (FALSE)

For X =5.8 ft

$Z=\frac{X-\mu}{\sigma}\\Z=\frac{5.8-5}{0.4}=2$

Therefore, a tree with a height of 5.8 ft is 2 standard deviation above the mean.

⇒ $4^t^h$ statement:A tree with a height of 6.2 ft is 3 standard deviations above the mean. (TRUE)

For X =6.2\ ft

$Z=\frac{X-\mu}{\sigma}\\Z=\frac{6.2-5}{0.4}=3$

Therefore, a tree with a height of 6.2 ft is 3 standard deviations above the mean.

6 0

3 years ago