Consider the following sets of sample data: A: $29,400, $30,900, $21,000, $33,200, $21,300, $24,600, $29,500, $22,500, $35,200,
Lana71 [14]
Answer:
CV for A = 21.8%
CV for B = 15.5%
Step-by-step explanation:
The formula for coefficient of variation is:
CV = Standard Deviation / Mean
So,
For A:
Mean = Sum/No. of items
= 391300/14
=$27950
and
SD = $6085.31
CV for A = 6085.31/27950 * 100
=21.77%
Rounding off to one decimal
CV for A = 21.8%
For B:
Mean = Sum/No. of items
= 43.58/11
=3.96
and
SD = 0.615
CV for B = 0.615/3.96 * 100
=15.53%
=15.5% ..
Assume a is not divisible by 10. (otherwise the problem is trivial).
<span>Define R(m) to be the remainder of a^m when divided by 10. </span>
<span>R can take on one of 9 possible values, namely, 1,2,...,9. </span>
<span>Now, consider R(1),R(2),......R(10). At least 2 of them must have the sames value (by the Pigeonhole Principle), say R(i) = R(j) ( j>i ) </span>
<span>Then, a^j - a^i is divisible by 10.</span>
