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Anton [14]
3 years ago
14

Consider the following sets of sample data: A: $29,400, $30,900, $21,000, $33,200, $21,300, $24,600, $29,500, $22,500, $35,200,

$20,800, $39,800, $22,300, $35,700, $25,100 B: 4.53, 4.17, 4.48, 3.73, 3.83, 2.91, 2.99, 4.67, 4.21, 4.68, 3.38 Step 1 of 2 : For each of the above sets of sample data, calculate the coefficient of variation, CV. Round to one decimal place.
Mathematics
1 answer:
Lana71 [14]3 years ago
6 0

Answer:

CV for A = 21.8%

CV for B = 15.5%

Step-by-step explanation:

The formula for coefficient of variation is:

CV = Standard Deviation / Mean

So,

For A:

Mean = Sum/No. of items

= 391300/14

=$27950

and

SD = $6085.31

CV for A = 6085.31/27950 * 100

=21.77%

Rounding off to one decimal

CV for A = 21.8%

For B:

Mean = Sum/No. of items

= 43.58/11

=3.96

and

SD = 0.615

CV for B = 0.615/3.96 * 100

=15.53%

=15.5% ..

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ACD is a triangle and B is a point on AC. AB = 8cm and BC is 6cm. Angle BCD = 48° and angle BDC = 50°. (a) Find the length of BD
FromTheMoon [43]

Answer:

  • 5.8206 cm
  • 10.528 cm
  • 23.056 cm^2

Step-by-step explanation:

(a) The Law of Sines can be used to find BD.

  BD/sin(48°) = BD/sin(50°)

  BD = (6 cm)(sin(48°)/sin(60°)) ≈ 5.82064 cm

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(b) We can use the Law of Cosines to find AD.

  AD^2 = AB^2 +BD^2 -2·AB·BD·cos(98°) . . . . . angle ABD = 48°+50°

  AD^2 ≈ 110.841

  AD ≈ √110.841 ≈ 10.5281 . . . cm

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(c) The area of ∆ABD can be found using the formula ...

  A = ab·sin(θ)/2 . . . . . where a=AB, b=BD, θ = 98°

  A = (8 cm)(5.82064 cm)sin(98°)/2 ≈ 23.0560 cm^2

_____

Angle ABD is the external angle of ∆BCD that is the sum of the remote interior angles BCD and BDC. Hence ∠ABD = 48° +50° = 98°.

5 0
3 years ago
(PLZ HELP I ONLY HAVE 11 DAYS LEFT OF SCHOOL) If Wendell were to slice the doghouse with a plane parallel to the two sides throu
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a shape of a right triangle

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Solve: x2 − x − 6/x2 = x − 6/2x + 2x + 12/x After multiplying each side of the equation by the LCD and simplifying, the resultin
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The resulting equation after simplyfing the given equation is 3x^2 + 20x + 12 = 0 and whoose solutions are x = -2/3 or x = -6.

According to the given question.

We have an equation

\frac{x^{2}-x-6 }{x^{2} } = \frac{x-6}{2x} +\frac{2x+12}{x}

So, to find the resulting equation of the above equation we need to simplify.

First we will take LCD

\frac{x^{2} -x - 6 }{x^{2} } = \frac{x -6+2(2x + 12)}{2x}

\implies \frac{x^{2}-x-6 }{x^{2} } =\frac{x-6+4x+24}{2x}

\implies \frac{x^{2}-x-6 }{x^{2} } = \frac{5x +18}{2x}

Multiply both the sides by x.

\frac{x^{2}-x-6 }{x} = \frac{5x+18}{2}

Again multiply both the sides by x

2x^{2} -2x-12 = 5x^{2} +18x

\implies 5x^{2} -2x^{2} +18x +2x +12 = 0

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Factorize the above equation

⇒3x(x+6)+2(x+6) = 0

⇒(3x + 2)(x+6) = 0

⇒ x = -2/3 or x = -6

Hence, the resulting equation after simplyfing the given equation is 3x^2 + 20x + 12 = 0 and whoose solutions are x = -2/3 or x = -6.

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7 0
1 year ago
Solve the following <br><br><br> C^2-14=5c
kipiarov [429]

Answer:

c = - 2, c = 7

Step-by-step explanation:

Given

c² - 14 = 5c ( subtract 5c from both sides )

c² - 5c - 14 = 0 ← in standard form

To factorise the quadratic

Consider the factors of the constant term (- 14) which sum to give the coefficient of the c- term (- 5)

The factors are - 7 and + 2, since

- 7 × 2 = - 14 and - 7 + 2 = - 5, hence

(c - 7)(c + 2) = 0

Equate each factor to zero and solve for c

c - 7 = 0 ⇒ c = 7

c + 2 = 0 ⇒ c = - 2

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I need to write an expression to represent the volume of this shape
Alina [70]

Answer:

v = 3.14x²y

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volume cylinder = πr²h

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h = y

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