Which of the following scenarios would prevent a population from being in Hardy-Weinberg equilibrium?

Biology

1 answer:

OlgaM077 [116]3 years ago

3 0

Answer:

Explanation:

One of the assumptions of the Hardy Weinberg equilibrium is that the population should not experience mutations. Mutations are usually the base on which natural selection acts by selecting the advantageous alleles and weeding out the disadvantageous ones. This is how populations evolve.

Other assumptions of this equilibrium are; there should be no migration (hence gene flow), the population is infinitely large, and mating is random.

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GLYCOLYSIS :- Glycolysis is the metabolic pathway that converts glucose C₆H₁₂O₆, into pyruvic acid, CH₃COCOOH. The free energy released in this process is used to form the high-energy molecules adenosine triphosphate and reduced nicotinamide adenine dinucleotide
PRODUCTS :- Glycolysis produces 2 ATP, 2 NADH, and 2 pyruvate molecules: Glycolysis, or the aerobic catabolic breakdown of glucose, produces energy in the form of ATP, NADH, and pyruvate, which itself enters the citric acid cycle to produce more energy.
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Reaction 1: glucose phosphorylation to glucose 6-phosphate.
Reaction 2: isomerization of glucose 6-phosphate to fructose 6-phosphate
Reaction 3: phosphorylation of fructose 6-phosphate to fructose 1,6-bisphosphate
Reaction 4: cleavage of fructose 1,6-bisphosphate into two three-carbon fragments.

Explanation:

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