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3 years ago

Which of the following statements are true regarding technology and learning? Select 3 options.

Computers and Technology

1 answer:

bekas [8.4K]3 years ago

5 0

Answer:

<h2>Knowledge can be acquired throughout your life, through both formal and informal methods.</h2>

As long as a person is alive, they can keep learning. With the amount of knowledge available in the world, it is improbable that a person can acquire all of it before they pass on. It is therefore possible to acquire information until the day a person dies.

<h2>Changes in technology both enable and require lifelong learning.</h2>

Technology keeps changing and developing in order to make things better and more efficient. As such, humans need to keep learning for their entire lives or else they will be left behind as newer technology comes out. Take smartphones for instance, a lot of older grandparents have had to learn how to use them to keep in contact with with their families.

<h2>Virtual reality simulations are being used for training in industries like healthcare and the armed forces.</h2>

Virtual reality has improved the effectiveness of training in both the medical and armed forces industry because with training capable of being done in a virtual world, it can be more in-depth. For instance, medical students can use more realistic subjects to learn the intricacies of the human body and soldiers can embark on dangerous training missions without actually risking their lives.

You might be interested in

Write a program that prompts the user to enter in a postive number. Only accept positive numbers - if the user supplies a negati

marusya05 [52]

Answer:

The c++ program to check prime numbers is shown below.

#include <iostream>

using namespace std;

int main() {

int num, prime=0;

{

cout<<"Enter a positive number."<<endl;

cin>>num;

if(num<1)

{

cout<<"Invalid number. Enter a positive number"<<endl;

cin>>num;

}

}while(num<1);

if(num==1 || num==2 || num==3)

cout<<num<<" is a prime number."<<endl;

else if(num%2 == 0)

cout<<num<<" is not a prime number."<<endl;

else

{

for(int k=3; k<num/2; k++)

{

if(num%k == 0)

prime++;

}

if(prime>1)

cout<<num<<" is not a prime number."<<endl;

else

cout<<num<<" is a prime number."<<endl;

}

OUTPUT

Enter a positive number.

-7

Invalid number. Enter a positive number

Enter a positive number.

79 is a prime number.

Explanation:

The user input is validated for positivity. A do while loop along with an if statement is implemented for verification.

{

cout<<"Enter a positive number."<<endl;

cin>>num;

if(num<1)

{

cout<<"Invalid number. Enter a positive number"<<endl;

cin>>num;

}

}while(num<1);

The test for prime number is done by using multiple if else statements.

If user inputs 1, 2, or 3, message is displayed.

Else If user inputs an even number, message is displayed for not prime. This is done by taking modulo of the number upon division by 2.

Else if user inputs neither an even number nor a number less than 3, the modulus of the number is taken with divisors beginning from 3 up to half of the input number.

For this, an integer variable prime is initialized to 0. A number can be completely divisible by itself or by its factors.

If the number is divisible by any of the divisors, value of variable prime is increased by 1. If value of prime is greater than 1, this means that the user input is divisible by more than one divisor. Hence, the given number is not a prime number.

5 0

3 years ago

Text line breaks and returns are controlled using which tags?

eduard

<b></b> <span>element when used to strongly emphasize portions of text within a document.
<p></p> </span><span>tag defines a paragraph.
<ol></ol> </span><span>Defines an ordered list
<a></a> </span><span> tag defines a hyperlink</span>

5 0

3 years ago

Read 2 more answers

Jack needs to improve sales on a local service for the elderly. What would be the best place for him to place an ad?

Lorico [155]

Answer: D

Local news channels

Explanation:

Since Jack is trying to improve local service the local news would be the best fit to reach the maximum amount of people in his area.

3 0

3 years ago

Read 2 more answers

Given a string variable string 's;', implement a tokenizer to identify the unique tokens contained in this string, identify all

Flauer [41]

Answer:

#include <iostream>

#include <string>

#include <vector>

#include <cctype>

#include <algorithm>

using namespace std;

void matrixInit( vector< vector<int> >& matrix, int numRows, int numCols);

struct TokenFreq{

string token;

int freq;

};

string spaces(string& istr, string& newstr);

void printVector(vector<TokenFreq> & tfVec);

void getTokenFreqVec( string& istr, vector<TokenFreq> & tfVecVec);

void selectionSort( vector<TokenFreq> & tokFreqVector );

void insertionSort( vector<TokenFreq> & tokFreqVector );

//main

int main(int argc, const char * argv[]) {

vector<vector<int> > matrix;

matrixInit(matrix, 3, 4);

string ostr1 = " I do keep the main points straight in my head most of the time, and I do know where to find the details when I need them. by Bjarne Stroustrup";

string ostr2 = " ";

string ostr3 = "Your time is limited, so don’t waste it living someone else’s life.Stay Hungry. Stay Foolish.";

//string ostr = ostr2;

string istr;

cout << "Enter the text: ";

getline(cin, istr);

vector<TokenFreq> tfVec;

getTokenFreqVec(istr, tfVec);

selectionSort(tfVec);

insertionSort(tfVec);

return 0;

}

//-----

void selectionSort( vector<TokenFreq> & tokFreqVector ){

TokenFreq temp;

int min;

for( int i = 0; i < int(tokFreqVector.size()-1); i++){

min = i;

for (int j = i+1; j <int(tokFreqVector.size()); j++){

if (tokFreqVector[j].freq < tokFreqVector[min].freq)

min = j;

}

if(min!=i)

{

temp = tokFreqVector[i];

tokFreqVector[i] = tokFreqVector[min];

tokFreqVector[min] = temp;

}

cout<<"-----selectionSort------------------"<<endl;

printVector(tokFreqVector);

}

void insertionSort( vector<TokenFreq> & tokFreqVector ){

TokenFreq temp;

int max;

for( int i = 0; i < int(tokFreqVector.size()-1); i++){

max = i;

for (int j = i+1; j < int(tokFreqVector.size()); j++){

if (tokFreqVector[j].freq > tokFreqVector[max].freq)

max = j;

}

if(max!=i)

{

temp = tokFreqVector[i];

tokFreqVector[i] = tokFreqVector[max];

tokFreqVector[max] = temp;

}

cout<<"-----insertionsort------------------"<<endl;

printVector(tokFreqVector);

}

string spaces(string& istr, string & newstr){

int j;

//Check double space and create new string with lowercase

for (int i = 0; i < int(istr.length()); ++i){

istr[i] = tolower(istr[i]);

if (isspace(istr[i])){

//check double space again

j = i+1;

while(true){

if (istr[j] == '\342') istr[j]=' ';

if (istr[j] == '\200') istr[j]=' ';

if (istr[j] == '\224') istr[j]=' ';

if(isspace(istr[j])) j++;

else break;

}

i=j-1;

newstr = newstr + istr[i];

}else

newstr = newstr + istr[i];

}

return newstr;

}

void getTokenFreqVec( string& istr, vector<TokenFreq> & tfVec){

string newstr;

int curr_beg = 0;

int curr_end = 0;

string word;

bool check = false;

int index=0;

//call func spaces to get new string

newstr = spaces(istr, newstr);

//cout << newstr << endl;

//cout << endl;

//cout << newstr << "||" << endl;

string tempstr = newstr;

if(newstr != " "){

tfVec.push_back(TokenFreq());

}

for (int i = 0; i < int(newstr.length()); ++i){

if(isspace(newstr[i])){

check = false;

curr_end = i;

word = tempstr.substr(curr_beg, curr_end - curr_beg);

curr_beg = i + 1;

for (int j = 0; j < int(tfVec.size()); j++){

if (tfVec[j].token == word){

tfVec[j].freq++;

check = true;

break;

}

}//end-for;

if (check == false && i!=(int(newstr.length())-1)){

//cout <<"**"<< word <<"**"<<word.length()<< endl;

tfVec[index].token=word;

tfVec[index].freq=1;

index++;

tfVec.push_back(TokenFreq());

}

word = "";

//add last value

}

}//end-for

if(!isspace(newstr[int(newstr.length())-1])){

word = tempstr.substr(curr_beg, curr_end - (int(newstr.length())-1));

tfVec[index].token=word;

tfVec[index].freq=1;

//tfVec.push_back(TokenFreq());

}

printVector(tfVec);

}

void printVector(vector<TokenFreq> & tfVec){

cout << "size= {" << tfVec.size() << endl;

for (int i = 0; i < int(tfVec.size()); i++){

cout << " [" << i << "] = (token = \""<< tfVec[i].token <<"\", freq = " << tfVec[i].freq << ")" << endl;

//cout << tfVec[i].token<<endl;;

}

cout << endl;

}

void matrixInit( vector< vector<int> >& matrix, int numRows, int numCols){

int i;

int j;

matrix.resize(numRows, vector<int>(numCols) );

for(i = 0; i< numRows; i++ ){

for(j = 0; j < numCols; j++ )

matrix[i][j] = i*j;

}

cout << "size of matrix is: " << numRows << "x" << numCols << endl;

for (i = 0; i < numRows; i++){

for (j = 0; j < numCols; j++){

cout<< "matrix[" << i << "][" << i << "]=" << matrix[i][j] << endl;

}

cout << endl;

}

Explanation:

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3 years ago

Tasha purchased a new tablet. She has several questions about how to connect to the internet, download apps, install software, a

lutik1710 [3]

The answer is D because a toutourial can explain each and everey process

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3 years ago