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nignag [31]
3 years ago
14

Which of the following statements are true regarding technology and learning? Select 3 options.

Computers and Technology
1 answer:
bekas [8.4K]3 years ago
5 0

Answer:

<h2>Knowledge can be acquired throughout your life, through both formal and informal methods.</h2>

As long as a person is alive, they can keep learning. With the amount of knowledge available in the world, it is improbable that a person can acquire all of it before they pass on. It is therefore possible to acquire information until the day a person dies.

<h2>Changes in technology both enable and require lifelong learning.</h2>

Technology keeps changing and developing in order to make things better and more efficient. As such, humans need to keep learning for their entire lives or else they will be left behind as newer technology comes out. Take smartphones for instance, a lot of older grandparents have had to learn how to use them to keep in contact with with their families.

<h2>Virtual reality simulations are being used for training in industries like healthcare and the armed forces.</h2>

Virtual reality has improved the effectiveness of training in both the medical and armed forces industry because with training capable of being done in a virtual world, it can be more in-depth. For instance, medical students can use more realistic subjects to learn the intricacies of the human body and soldiers can embark on dangerous training missions without actually risking their lives.

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Sketch f(x) = 5x2 - 20 labelling any intercepts.​
Norma-Jean [14]

Answer:

  • The graph of the function is attached below.
  • The x-intercepts will be: (2, 0), (-2, 0)
  • The y-intercept will be: (-20, 0)

Explanation:

Given the function

f\left(x\right)\:=\:5x^2-\:20

As we know that the x-intercept(s) can be obtained by setting the value y=0

so

y=\:5x^2-\:20

switching sides

5x^2-20=0

Add 20 to both sides

5x^2-20+20=0+20

5x^2=20

Dividing both sides by 5

\frac{5x^2}{5}=\frac{20}{5}

x^2=4

\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

x=\sqrt{4},\:x=-\sqrt{4}

x=2,\:x=-2

so the x-intercepts will be: (2, 0), (-2, 0)

we also know that the y-intercept(s) can obtained by setting the value x=0

so

y=\:5(0)^2-\:20

y=0-20

y=-20

so the y-intercept will be: (-20, 0)

From the attached figure, all the intercepts are labeled.

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D

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