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olganol [36]
3 years ago
13

Given a string variable string 's;', implement a tokenizer to identify the unique tokens contained in this string, identify all

the unique tokens and their frequencies, and store such information into a vector. Tokens are sequences of contiguous characters separated by any of the specified delimiters (e.g., white spaces). In this lab, only white spaces will be considered as delimiters. For instance, the string "Hello, what's that thing? " contains four tokens: "Hello", "what's", "that" and "thing?". The frequency of a token is the number of times this token appears in this string. In this example, each token has a frequency of 1. Note that in this lab, these tokens are case insensitive. For example, "Hello" and "hello" are considered to be the same token.
Specifically, you are required to declare a struct TokenFreq that consists of two data members: (1) string token; and (2) int freq; Obviously, an object of this struct will be used to store a specific token and its frequency. For example, the following object word stores the token "dream" and its frequency 100:

TokenFreq word;
word.value="dream";
word.freq=100;

implement the following function, where istr is the input string, and tfVec will be used to store the list of unique and case insensitive tokens and their corresponding frequencies identified within istr. You might find it's very convenient to use stringstream objects to tokenize a string.

void getTokenFreqVec( const string& istr, vector & tfVec)
Assume that the value of istr is

And no, I'm not a walking C++ dictionary. I do not keep every technical detail in my head at all times. If I did that, I would be a much poorer programmer. I do keep the main points straight in my head most of the time, and I do know where to find the details when I need them. by Bjarne Stroustrup
After calling the above function, tfVec is expected to contain the following values (where order of appearances doesn't matter):

size=46 {
[0] = (token = "and", freq = 2)
[1] = (token = "no,", freq = 1)
[2] = (token = "i'm", freq = 1)
[3] = (token = "not", freq = 2)
[4] = (token = "a", freq = 2)
[5] = (token = "walking", freq = 1)
[6] = (token = "c++", freq = 1)
[7] = (token = "dictionary.", freq = 1)
[8] = (token = "i", freq = 6)
[9] = (token = "do", freq = 3)
[10] = (token = "keep", freq = 2)
[11] = (token = "every", freq = 1)
[12] = (token = "technical", freq = 1)
[13] = (token = "detail", freq = 1)
[14] = (token = "in", freq = 2)
[15] = (token = "my", freq = 2)
[16] = (token = "head", freq = 2)
[17] = (token = "at", freq = 1)
[18] = (token = "all", freq = 1)
[19] = (token = "times.", freq = 1)
[20] = (token = "if", freq = 1)
[21] = (token = "did", freq = 1)
[22] = (token = "that,", freq = 1)
[23] = (token = "would", freq = 1)
[24] = (token = "be", freq = 1)
[25] = (token = "much", freq = 1)
[26] = (token = "poorer", freq = 1)
[27] = (token = "programmer.", freq = 1)
[28] = (token = "the", freq = 3)
[29] = (token = "main", freq = 1)
[30] = (token = "points", freq = 1)
[31] = (token = "straight", freq = 1)
[32] = (token = "most", freq = 1)
[33] = (token = "of", freq = 1)
[34] = (token = "time,", freq = 1)
[35] = (token = "know", freq = 1)
[36] = (token = "where", freq = 1)
[37] = (token = "to", freq = 1)
[38] = (token = "find", freq = 1)
[39] = (token = "details", freq = 1)
[40] = (token = "when", freq = 1)
[41] = (token = "need", freq = 1)
[42] = (token = "them.", freq = 1)
[43] = (token = "by", freq = 1)
[44] = (token = "bjarne", freq = 1)
[45] = (token = "stroustrup", freq = 1)
Required:
Implement the selection sort algorithm to sort a vector in ascending order of token frequency. This function has the following prototype:

void selectionSort( vector & tokFreqVector );
//This function receives a vector of TokenFreq objects by reference and applies the selections sort algorithm to sort this vector in increasing order of token frequencies.
Implement the insertion sort algorithm to sort a vector in descending order of token frequency.
Computers and Technology
1 answer:
Flauer [41]3 years ago
3 0

Answer:

#include <iostream>

#include <string>

#include <vector>

#include <cctype>

#include <algorithm>

using namespace std;

void matrixInit( vector< vector<int> >& matrix, int numRows, int numCols);

struct TokenFreq{

string token;

int freq;

};

string spaces(string& istr, string& newstr);

void printVector(vector<TokenFreq> & tfVec);

void getTokenFreqVec( string& istr, vector<TokenFreq> & tfVecVec);

void selectionSort( vector<TokenFreq> & tokFreqVector );  

void insertionSort( vector<TokenFreq> & tokFreqVector );

//main

int main(int argc, const char * argv[]) {

 

vector<vector<int> > matrix;

matrixInit(matrix, 3, 4);

 

string ostr1 = " I do keep the main points straight in my head most of the time, and I do know where to find the details when I need them. by Bjarne Stroustrup";

string ostr2 = " ";

string ostr3 = "Your time is limited, so don’t waste it living someone else’s life.Stay Hungry. Stay Foolish.";

//string ostr = ostr2;

string istr;

 

cout << "Enter the text: ";

getline(cin, istr);

vector<TokenFreq> tfVec;

getTokenFreqVec(istr, tfVec);

selectionSort(tfVec);

insertionSort(tfVec);

return 0;

}

//-----

void selectionSort( vector<TokenFreq> & tokFreqVector ){

TokenFreq temp;

int min;

 

for( int i = 0; i < int(tokFreqVector.size()-1); i++){

min = i;

for (int j = i+1; j <int(tokFreqVector.size()); j++){

if (tokFreqVector[j].freq < tokFreqVector[min].freq)

min = j;

}

if(min!=i)

{

temp = tokFreqVector[i];

tokFreqVector[i] = tokFreqVector[min];

tokFreqVector[min] = temp;

}

}

cout<<"-----selectionSort------------------"<<endl;

printVector(tokFreqVector);

}

void insertionSort( vector<TokenFreq> & tokFreqVector ){

TokenFreq temp;

int max;

 

for( int i = 0; i < int(tokFreqVector.size()-1); i++){

max = i;

for (int j = i+1; j < int(tokFreqVector.size()); j++){

if (tokFreqVector[j].freq > tokFreqVector[max].freq)

max = j;

}

if(max!=i)

{

temp = tokFreqVector[i];

tokFreqVector[i] = tokFreqVector[max];

tokFreqVector[max] = temp;

}

}

cout<<"-----insertionsort------------------"<<endl;

printVector(tokFreqVector);

}

string spaces(string& istr, string & newstr){

int j;

//Check double space and create new string with lowercase

for (int i = 0; i < int(istr.length()); ++i){

istr[i] = tolower(istr[i]);

if (isspace(istr[i])){

//check double space again

j = i+1;

while(true){

if (istr[j] == '\342') istr[j]=' ';

if (istr[j] == '\200') istr[j]=' ';

if (istr[j] == '\224') istr[j]=' ';

if(isspace(istr[j])) j++;

else break;

}

i=j-1;

newstr = newstr + istr[i];

}else

newstr = newstr + istr[i];

}

return newstr;

}

void getTokenFreqVec( string& istr, vector<TokenFreq> & tfVec){

string newstr;

int curr_beg = 0;

int curr_end = 0;

string word;

bool check = false;

int index=0;

 

//call func spaces to get new string

newstr = spaces(istr, newstr);

//cout << newstr << endl;

//cout << endl;

//cout << newstr << "||" << endl;

string tempstr = newstr;

 

if(newstr != " "){

tfVec.push_back(TokenFreq());

}

for (int i = 0; i < int(newstr.length()); ++i){

if(isspace(newstr[i])){

check = false;

 

curr_end = i;

word = tempstr.substr(curr_beg, curr_end - curr_beg);

curr_beg = i + 1;

 

for (int j = 0; j < int(tfVec.size()); j++){

if (tfVec[j].token == word){

tfVec[j].freq++;

check = true;

 

break;

}

}//end-for;

if (check == false && i!=(int(newstr.length())-1)){

//cout <<"**"<< word <<"**"<<word.length()<< endl;

tfVec[index].token=word;

tfVec[index].freq=1;

index++;

tfVec.push_back(TokenFreq());

}

word = "";

//add last value

}

}//end-for

 

if(!isspace(newstr[int(newstr.length())-1])){

word = tempstr.substr(curr_beg, curr_end - (int(newstr.length())-1));

tfVec[index].token=word;

tfVec[index].freq=1;

//tfVec.push_back(TokenFreq());

}

 

printVector(tfVec);

}

void printVector(vector<TokenFreq> & tfVec){

 

cout << "size= {" << tfVec.size() << endl;

for (int i = 0; i < int(tfVec.size()); i++){

cout << " [" << i << "] = (token = \""<< tfVec[i].token <<"\", freq = " << tfVec[i].freq << ")" << endl;

//cout << tfVec[i].token<<endl;;

}

cout << endl;

}

void matrixInit( vector< vector<int> >& matrix, int numRows, int numCols){

int i;

int j;

matrix.resize(numRows, vector<int>(numCols) );

for(i = 0; i< numRows; i++ ){

for(j = 0; j < numCols; j++ )

matrix[i][j] = i*j;

}

 

cout << "size of matrix is: " << numRows << "x" << numCols << endl;

for (i = 0; i < numRows; i++){

for (j = 0; j < numCols; j++){

cout<< "matrix[" << i << "][" << i << "]=" << matrix[i][j] << endl;

}

}

cout << endl;

}

Explanation:

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Be able to list a technology-based company and discuss whether it enjoys sustainable competitive advantage based on the resource
aev [14]

Answer:

idk good luck finding one

5 0
3 years ago
Write a parent program to fork(2) n processes where n is passed tothe program on the command line, and n can be from 1 to 10. Al
MrRissso [65]

Answer:

Complete code is given below:

Explanation:

#include <stdio.h>

#include <sys/types.h>

#include <unistd.h>

#include <time.h>

#include <sys/wait.h>

int main(int argc , char *argv[]){

pid_t mypid, childpid;

int status;

int i,n;

time_t t;

     

mypid = getpid();

printf("pid is %d.\n", mypid);

childpid = fork();

if ( childpid == -1 ) {

perror("Cannot proceed. fork() error");

return 1;

}

 

 

if (childpid == 0) {

 

 

mypid = getpid();

 

 

childpid = fork();

if ( childpid == -1 ) {

perror("Cannot proceed. fork() error");

return 1;

}

 

if (childpid == 0) {

 

mypid = getpid();

printf("Child pid is %d.\n", getppid());

 

childpid = fork();

 

 

if ( childpid == -1 ) {

perror("Cannot proceed. fork() error");

return 1;

}

random((unsigned) time(&t));

printf(" parent id = %d : Random = %d\n",mypid , (int)(random()% 100 +1));

printf("child id = %d : Random = %d\n",getpid , (int)(random()% 100 +1));

 

if (childpid == 0) {

 

printf("Child 2: I hinerited my parent's PID as %d.\n", mypid);

 

mypid = getpid();

printf("Child 2: getppid() tells my parent is %d. My own pid instead is %d.\n", getppid(), mypid);

 

sleep(30);

return 12;

} else return 15;

} else {

 

while ( waitpid(childpid, &status,0) == 0 ) sleep(1);

 

if ( WIFEXITED(status) ) printf("Child 1 exited with exit status %d.\n", WEXITSTATUS(status));

else printf("Child 1: child has not terminated correctly.\n");

}

} else {

printf(" fork() is ok and child pid is %d\n", childpid);

wait(&status);

 

if ( WIFEXITED(status) ) printf(" child has exited with status %d.\n", WEXITSTATUS(status));

else printf(" child has not terminated normally.\n");

}

 

return 0;

}

Output:

pid is 24503.

Child   pid  is 24565.

parent id = 24566 : Random = 87

child id = 1849900480 : Random = 78

pid is 24503.

Child 1  exited with exit status 15.

pid is 24503.

fork() is ok and child pid is  24565

child has exited with status 0.

6 0
3 years ago
By limiting the number of times a person can use a type of software before registering as the authorized owner of that software,
alexira [117]

Answer:

Software piracy.

Explanation:

A software can be defined as a set of executable instructions (codes) or collection of data that is used typically to instruct a computer on how to perform a specific task and solve a particular problem.

Simply stated, it's a computer program or application that comprises of sets of code for performing specific tasks on the system.

Basically, softwares are categorized into two (2) main categories and these are;

I. Open-source software.

II. Proprietary software.

A proprietary software is also known as a closed-source software and it can be defined as any software application or program that has its source code copyrighted and as such cannot be used, modified or distributed without authorization from the software developer. Thus, it is typically published as a commercial software that may be sold, licensed or leased by the software developer (vendor) to the end users with terms and conditions.

Some examples of proprietary software are Microsoft Windows, macOS, Adobe photoshop etc.

Furthermore, a proprietary software license avail end users the opportunity to install and use the software after agreeing to the terms of its license.

Software piracy can be defined as an act which typically involves the unauthorized use, duplications, or distribution of a software that is legally copyrighted or protected, without an express permission from the software manufacturer (owner).

Generally, software manufacturers (owners) deal with problems associated with software piracy by placing a limit on the number of times or durations that an end user is allowed to use a particular software before registering (subscribing) as the authorized owner of that software.

8 0
3 years ago
Which of the following is a special-purpose computer that functions as a component in a larger product?
Dominik [7]

Answer:  

Embedded Computer

Explanation:

  • An embedded computer is designed to perform a certain function and it is a component of a larger system.
  • An embedded computer has a dedicated function within a larger system and is incorporated as a part of a complete system rather than being a stand alone computer.
  • It is a microprocessor, micro controller based real time control system.
  • Its a combination of hardware and software that have a dedicated function to achieve a specific task. The also have peripheral devices for communication purposes.  
  • Digital Camera , ATM, Calculator, Digital Watch , Self-autonomous Vehicles, Security Camera , Washing Machine , Mp3 player, Microwave Oven , Fire Alarm, Smart Phone,Vending Machines, networking hardware like dedicated routers etc are examples of embedded systems.
  • Embedded computers are less expensive to produce, consumes less power, easier to maintain, do not require remote maintenance and easily customizable.

4 0
3 years ago
Which of the following statement is False? 1 point Context free language is the subset of context sensitive language Regular lan
alisha [4.7K]

Answer:

Context-sensitive language is a subset of context-free language

Explanation:

Considering the available options, the statement that is considered wrong is "Context-sensitive language is a subset of context-free language."

This is because generally every regular language can be produced through the means of context-free grammar, while context-free language can be produced through the means of context-sensitive grammar, and at the same time, context-sensitive grammars are produced through the means of Recursively innumerable.

Hence, the correct answer in this correct answer to the question is the last option *Context-sensitive language is a subset of context-free langage

3 0
3 years ago
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