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mafiozo [28]
3 years ago
5

In parallelogram DEFG, DH = x + 3, HF = 3y, GH = 2x – 5, and HE = 5y + 2. Find the values of x and y.

Mathematics
1 answer:
eimsori [14]3 years ago
3 0
Since DH=HF you set x+3=3y 
<span>GH=HE so 4x-5=2y+3 </span>

<span>This gives you a system and I solved by substitution so I got x alone in the first equation-> x=3y-3 </span>
<span>then I plugged this x into the second equation so </span>

<span>4(3y-3)-5=2y+3 </span>
<span>12y-12-5=2y+3 </span>
<span>12y-17=2y+3 </span>
<span>10y=20 </span>
<span>y=2 </span>

<span>plug y into the first equation to find x </span>
<span>x=3(2)-3 </span>
<span>x=6-3 </span>
<span>x=3 </span>

<span>c. x=3, y=2</span>
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