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4 years ago

In parallelogram DEFG, DH = x + 3, HF = 3y, GH = 2x – 5, and HE = 5y + 2. Find the values of x and y.

1 answer:

3 0

Since DH=HF you set x+3=3y
GH=HE so 4x-5=2y+3 

This gives you a system and I solved by substitution so I got x alone in the first equation-> x=3y-3 
then I plugged this x into the second equation so 

4(3y-3)-5=2y+3 
12y-12-5=2y+3 
12y-17=2y+3 
10y=20 
y=2 

plug y into the first equation to find x 
x=3(2)-3 
x=6-3 
x=3 

c. x=3, y=2

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3 years ago

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s2008m [1.1K]

Answer:

x = -3

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Step-by-step explanation:

Given equations :- 

-x + 2y = 3 ....... ( i )

2x - 3y = -6 ....... ( ii )

From ( i ) 

-x + 2y = 3

-x = 3 - 2y

x = 2y - 3 ........ ( iii )

From ( ii ) 

2x - 3y = -6

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$x = \frac{ - 6 + 3y}{2}$

........ ( iv )

Equating ( iii ) and ( iv )

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4 0

3 years ago

On Friday, 80 children and 48 adults went to a movie. What was the ratio of children to adults? A 5 to 3 B 10 to 4 C 6 to 3 D 2

Setler79 [48]

A . Because one you make the ratio 80:48 you simplify (divide until you can divide anymore ).

7 0

3 years ago

Read 2 more answers

Help help help help

Alex

Answer:

Step-by-step explanation:

4b+5=t

First, you must get the variable alone! Substract 5 from both sides!

4b+5=t

-5 -5

The 5 cancels out because 5-5=0

The new equation is 4b=t-5

You must divide by 4 to get the variable alone since your solving for b!

4b=t-5

4 4

b= $\frac{t-5}{4} \\$

This is your answer!

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3 years ago

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miss Akunina [59]

Answer:

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Step-by-step explanation:

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3 years ago