What does the expression 0.30y represent ?
1 answer:
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Answer:
-12
Step-by-step explanation:
Let b = -1 and a = -3
The average rate of change =
f(b) = f(-1) = 3(-1)^2 - 5 = 3 - 5 = -2
f(a) = f(-3) = 3(-3)^2 - 5 =27 - 5 = 22
f(b) - f(a) = -2 - 22 = -24
b - a = -1 + 3 = 2
= -24/2 = -12
suppose the people have weights that are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Find the probability that if a person is randomly selected, his weight will be greater than 174 pounds?
Assume that weights of people are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Mean = 177
standard deviation = 26
We find z-score using given mean and standard deviation
z =
=
=-0.11538
Probability (z>-0.11538) = 1 - 0.4562 (use normal distribution table)
= 0.5438
P(weight will be greater than 174 lb) = 0.5438