To solve Q.15, remember to multiply the first numerical coefficient, in this case 3 to -12, to find the numbers to multiply and get that product. The middle term represents the sum the same two numbers must add to.
For example:
3r^2 - 16r - 7 = 5
3r^2 - 16r - 12 = 0
What 2 numbers multiply to give you -36, and add to give you -16, are -18 and +2, since -18 • 2 = -36, and -18 + 2 = -16.
3r^2 - 18r + 2r - 12 = 0
Factor
3r(r - 6) + 2(r - 6) = 0
(3r + 2)(r - 6) = 0
r = 6
3r + 2 = 0
3r = -2
r = -2/3.
Your 2 solutions for r are -2/3 and 6.
-5x+y=-2
y=5x-2
-3x+6(5x-2)=-12
-3x+30x-12=-12
27x-12=-12
27x= 0
x= (0/27)
x=0
-5(0)+y=-2
0+y=-2
y=-2
The volume of a cone is 1/3Bh. The base is pi times the radius squared, so the base is 16 pi. 32 pi = 1/3 • 16 pi • h. 32 pi = 16/3 pi • h. Divide 32 pi by 16/3 pi to find the height, which equals 6.
You have to use your area equations.like basex height
Answer:
The first one can be anything as long as it has y=-7x
Second, the solution for the equations is (3 3/4, 0), I found that by using the elimination method. I don’t remember how to do the rest, I’m sorry