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Nastasia [14]
3 years ago
8

What is this? Please answer with an explanation

Mathematics
1 answer:
Colt1911 [192]3 years ago
8 0

Answer:

No

Step-by-step explanation:

Given

f(x) = \sqrt{x-10} + 11 ← substitute x = 1

f(1) = \sqrt{1-10} + 11

     = \sqrt{-9} + 11

\sqrt{-9}  is not real and therefore x = 1 does not have a real output for f(x)

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