Question

What is this? Please answer with an explanation

Answer 1

Answer:

No

Step-by-step explanation:

Given

f(x) = $\sqrt{x-10}$ + 11 ← substitute x = 1

f(1) = $\sqrt{1-10}$ + 11

     = $\sqrt{-9}$ + 11

$\sqrt{-9}$  is not real and therefore x = 1 does not have a real output for f(x)