3 years ago

What is this? Please answer with an explanation

Mathematics

1 answer:

Colt1911 [192]3 years ago

8 0

Answer:

Step-by-step explanation:

Given

f(x) = $\sqrt{x-10}$ + 11 ← substitute x = 1

f(1) = $\sqrt{1-10}$ + 11

= $\sqrt{-9}$ + 11

$\sqrt{-9}$ is not real and therefore x = 1 does not have a real output for f(x)

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