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MaRussiya [10]
3 years ago
10

Convert the following hexadecimal numbers to decimal: (a) FF (b) F0A2 (c) 0F100 (d) 100

Computers and Technology
1 answer:
Hatshy [7]3 years ago
8 0

Answer:

a) 255

b) 61602

c)

d)

Explanation:

You need to understand the decimal equivalent of hexadecimal numbers, <em>from 0 to 9 numbers are represented the same way, from 10 to 15 we use the alphabet, meaning 10 equals A in hexadecimal base, 11-B, 12-C, 13-D, 14-E, and 15-F.</em>

For your first exercise you'll enumerate the number's positions fromright to lef begining with 0:

a.               F   F

position    1    0

Now you'll multiply your hexadecimal number (using the decimal equivalent for your letters) for the base (16) elevated to the number of the position:

F*16^{0}=15*1=15\\F*16^{1}=15*16=240

Finally, you'll add your results:

240+15=255

FF=255

b.             F  0  A  2

position   3  2  1   0

2*16^{0}=2*1=2\\A*16^{1}=10*16=160\\0*16^{2}=0*256=0\\F*16^{3}=16*4096=61440\\\\2+160+0+61440=61602\\

F0A2=61602

c.             F  1  0  0

position   3  2  1   0

0*16^{0}=0*1=0\\0*16^{1}=0*16=0\\1*16^{2}=1*256=256\\F*16^{3}=16*4096=61440\\0+0+256+61440=61696\\

0F100=61696

d.              1  0  0

position  2  1   0

0*16^{0}=0*1=0\\0*16^{1}=0*16=0\\1*16^{2}=1*256=256\\\\0+0+256=256\\

100=256

I hope you find this information useful! Good luck!

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Answer:

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Explanation:

Main : From here the execution of the program begins

Set OldPrice = 100  -> This line assigns 100 to the OldPrice variable

Set SalePrice = 70   -> This line assigns 70to the SalePrice variable

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End Program -> the main program ends

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Set Sale = Cost * .80  -> This line multiplies the value of Cost with 0.80 and assigns the result to Sale variable

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So when the method BigSale is called two arguments are passed to it OldPrice argument and SalePrice is passed by reference.

The value of OldPrice is 100 and SalePrice is 70

Now when method BigSale is called, the reference &Sale is used to access actual argument SalePrice = 70

In the body of this method there are two statements:

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So when these statement execute:

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Any changes made to value of Sale will affect the value of SalePrice as it is passed by reference. So when the Write "A jacket that originally costs $ " + OldPrice Write "is on sale today for $ " + SalePrice statement executes, the value of OldPrice remains 100 same as it does not affect this passed argument, but SalePrice was passed by reference so the changes made to &Sale by statement in method BigSale i.e.  Sale = Cost * .80; has changed the value of SalePrice from 70 to 80 because Sale = 100 * 0.80 = 80. So the output produced is:

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