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Molodets [167]
3 years ago
9

What type of survey can help a network administrator make decisions about bands, channels, and widths when installing new access

points? a. wireless b. site c. architectural d. frequency
Computers and Technology
1 answer:
katrin2010 [14]3 years ago
4 0

Answer:

b. site

Explanation:

According to my research on information technology, I can say that based on the information provided within the question the best type of survey for this situation would be a site survey. This is because this is a survey whose main goal is to determine the best locations for access points and other infrastructure devices, and provide information for necessary planning.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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Asymmetric digital subscriber line (ADSL)
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An example of documentary evidence that might be presented at trial for a cyber crime is:
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2. Design a class named Sandwich with data fields for description and price. Include a constructor that requires arguments for b
marta [7]

Answer:

The answer files have been attached below, with the description of the files in the explanation.

Explanation:

The Sandwich class contains two functions

1) Sandwich() : A constructor that takes two arguments, the Description of sandwich and its price.

2) display_Data(): A function that does not take any arguments, and does not return anything. It prints the states (data of the variables Description, Price )

The Delivery Sandwich has three functions:

1) DeliverySandwich(): A constructor that takes in three arguments, Description of sandwich, Its price, and the delivery address.

super key word is used to access the parent class. super() is a method of calling the parent class's constructor. Description and price are passed to parent class's constructor, where as DeliveryAddress is initialized in the DeliverySandwich constructor.

It is then checked whether the price is greater than 15. If it is, the deliveryfee is set to 3, otherwise it is set to 5.

2) display_Data()

This is an overridden function. An overridden function in java is a function that has the same name as another function in its parent's class, but has different functionality.

The function first calls the display_Data() of the parent class using super.display_Data() to display the price and description of sandwich, then prints the address and delivery price of the sandwich

3) main()

Driver code that has objects of both sandwiches. Once an object is created, the display data function is called of each class to see the states of the variables in them.

Download java
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> java </span>
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> java </span>
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Two character strings may have many common substrings. Substrings are required to be contiguous in the original string. For exam
ryzh [129]

Answer:

Explanation:

The following function is written in Java. It takes two strings as parameters and calculates the longest substring between both of them and returns that substring length.

import java.util.*;

class Test

{

   public static void main(String[] args)

   {

       String X = "photograph";

       String Y = "tomography";

       System.out.println(X + '\n' + Y);

       System.out.println("Longest common substring length: " + longestSub(X, Y));

   }

   static int longestSub(String X, String Y)

   {

       char[] word1 = X.toCharArray();

       char[] word2 = Y.toCharArray();

       

       int length1 = X.length();

       int length2 = Y.length();

       int substringArray[][] = new int[length1 + 1][length2 + 1];

       int longestSubstringLength = 0;

       

       for (int i = 0; i <= length1; i++)

       {

           for (int j = 0; j <= length2; j++)

           {

               if (i == 0 || j == 0)

                   substringArray[i][j] = 0;

               else if (word1[i - 1] == word2[j - 1])

               {

                   substringArray[i][j]

                           = substringArray[i - 1][j - 1] + 1;

                   longestSubstringLength = Integer.max(longestSubstringLength,

                           substringArray[i][j]);

               }

               else

                   substringArray[i][j] = 0;

           }

       }

       return longestSubstringLength;

   }

}

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