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Vanyuwa [196]
3 years ago
15

How do you solve this kind of problem?

Mathematics
2 answers:
trasher [3.6K]3 years ago
4 0
-x•(83x-30)

Try and see if that's correct



Y_Kistochka [10]3 years ago
3 0
I hope this helps you

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A= 5,000 (1+.002*10)
Aneli [31]
I think The answer is 5100
3 0
3 years ago
The formula y y-y1=m(x-x1) please tell me what is m
grandymaker [24]

Answer:

There is no value in M

Step-by-step explanation:

The equation is undefined.

6 0
4 years ago
Let ​ f(x)=x2+5x−36 ​. Enter the x-intercepts of the quadratic function in the boxes.
san4es73 [151]
Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : 

                     x^2-5*x-(36)=0 

Step by step solution:<span> Step 1:</span> Trying to factor by splitting the middle term

<span> 1.1 </span>    Factoring <span> x2-5x-36</span> 

The first term is, <span> <span>x2</span> </span> its coefficient is 1.
The middle term is, <span> -5x </span> its coefficient is  - 5.
The last term, "the constant", is <span> -36 </span>

Step-1: Multiply the coefficient of the first term by the constant <span> <span> 1</span> • -36 = -36</span> 

Step-2: Find two factors of  -36  whose sum equals the coefficient of the middle term, which is - 5.

<span><span>     -36   +   1   =   -35</span><span>     -18   +   2   =   -16</span><span>     -12   +   3   =   -9</span><span>     -9   +   4   =   -5   That's it</span></span>


Step-3: Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -9  and  4 
                     <span>x2 - 9x</span> + 4x - 36

Step-4: Add up the first 2 terms, pulling out like factors :
                    x • (x-9)
              Add up the last 2 terms, pulling out common factors :
                    4 • (x-9)
Step-5: Add up the four terms of step 4 :
                    (x+4)  •  (x-9)
             Which is the desired factorization

<span>Equation at the end of step  1  :</span> (x + 4) • (x - 9) = 0 <span>Step  2  :</span>Theory - Roots of a product :

<span> 2.1 </span>   A product of several terms equals zero.<span> 

 </span>When a product of two or more terms equals zero, then at least one of the terms must be zero.<span> 

 </span>We shall now solve each term = 0 separately<span> 

 </span>In other words, we are going to solve as many equations as there are terms in the product<span> 

 </span>Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation :

<span> 2.2 </span>     Solve  :    x+4 = 0<span> 

 </span>Subtract  4  from both sides of the equation :<span> 
 </span>                     x = -4 

Solving a Single Variable Equation :

<span> 2.3 </span>     Solve  :    x-9 = 0<span> 

 </span>Add  9  to both sides of the equation :<span> 
 </span>                     x = 9 

6 0
4 years ago
Read 2 more answers
2/5 of a bag of soil fills 1/3 of a container, Is 1 bag of soil enough to fill 1 container?
natka813 [3]

Answer:

No.

Step-by-step explanation:

Let's find out if 1 bag of soil is enough to fill 1 container.

<u>Given:</u>

2/5 of a bag fills 1/3s of a containter.

With the given, multiplying 2/5 by 2.5 represents one. Multiply 1/3 by 2.5 aswell.

<u>Products:</u>

1, and 2.5/3 or 5/6

1 bag can fill 5/6 of a container.

Therefore, 1 bag can't fill 1 container.

7 0
3 years ago
SOLVE<br><br> 6/y+4 - 2/y-3 = 3<br><br> A. -5/3, -2<br> B. 5/3, -2<br> C. 5/3, 2<br> D. -5/3, 2
lbvjy [14]
Your answer D because that is how it turned out
3 0
3 years ago
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