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NISA [10]
4 years ago
12

which of the following cannot be the probality of an event a)1/2 b) 10% c) 0.7. d) 3/2. which is the correct option with the sol

ution​
Mathematics
1 answer:
prisoha [69]4 years ago
4 0

Answer:

D

Step-by-step explanation:

In probability,

a probability of 0 means that it is IMPOSSIBLE, sure that this event WILL NOT occur, ever. So, probability of anything less than 0 is not possible.

On the other hand, probability of 1 means that it is CERTAIN to happen. So, probabilty of anything greater than 1 can't happen.

So we can say:

0 <= Probability of an Event happening <= 1

Option A is 1/2, which is in the middle, so this is OKAY.

Option B is 10%, which is certainly close to 0 and between 0 and 1, so this is OKAY.

Option C is 0.7, which is close to 1 and greater than 0, so in between 0 and 1, certainly. So this is OKAY.

Option D is 3/2 which is 1.5, so this is GREATER THAN 1, so it can't ever be possible.

Option D is the correct choice.

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Answer:

y = kx

Step-by-step explanation:

In proportional relationships, the value of one variable increases as the other increases or decreases as the other decreases. It is denoted mathematically as  y ∝ x where x and y are the variables. It follows that

y = kx where k is the proportionality constant.

So in the relationship where x represents the number of adults, and y represents the number of students,

y ∝ x and y = kx

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A machine, when working properly, produces 5% or less defective items. Whenever the machine produces significantly greater than
vovikov84 [41]

Answer:

The pvalue of the test is 0.0007 < 0.01, which means that we reject the null hypothesis and accept the alternate hypothesis that the percentage of defective items produced by this machine is greater than 5%.

Step-by-step explanation:

A machine, when working properly, produces 5% or less defective items.

This means that the null hypothesis is:

H_0: p \leq 0.05

Test if the percentage of defective items produced by this machine is greater than 5%.

This means that the alternate hypothesis is:

H_a: p > 0.05

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.05 is tested at the null hypothesis:

This means that \mu = 0.05, \sigma = \sqrt{0.05*0.95}

A random sample of 300 items taken from the production line contained 27 defective items.

This means that n = 300, X = \frac{27}{300} = 0.09

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.09 - 0.05}{\frac{\sqrt{0.05*0.95}}{\sqrt{300}}}

z = 3.18

Pvalue of the test:

Testing if the mean is greater than a value, which means that the pvalue of the test is 1 subtracted by the pvalue of Z = 3.18, which is the probability of a finding a sample proportion of 0.09 or higher.

Looking at the Z-table, Z = 3.18 has a pvalue of 0.9993

1 - 0.9993 = 0.0007

The pvalue of the test is 0.0007 < 0.01, which means that we reject the null hypothesis and accept the alternate hypothesis that the percentage of defective items produced by this machine is greater than 5%.

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