The answer is x over x + 3.
Answer:
The distance of flag post from Y is 38.13 m
Step-by-step explanation:
Consider point Y at the intersection of both lines as shown below. Now the point X lies 34 meter from point Y in east direction.
Now flag pole at point X lies at a bearing of N18°W. That is at point X from north, flag post makes an angle of 18° towards west.
Similarly flag pole at point Y lies at a bearing of N40°E. That is at point Y from north, flag post makes an angle of 40° towards east.
Consider ∆ AXY as right angle triangle. Therefore measure of angle FXY is,



Consider ∆ BYX as right angle triangle. Therefore measure of angle FYX is,



Refer attachment 1.
From diagram consider the triangle FYX. To find the third angle that is ∠YFX can be calculated by using angle sum property of triangle.
∠YFX+∠FYX+∠FXY=180°
∠YFX+50°+72°=180°
∠YFX=58°
Refer attachment 2.
Now the distance FY can be calculated using sin rule as follows,

Substituting the values,

Simplifying first two terms,
Cross multiplying,


m
Consider the first equation : -3x-8=19.
Adding 8 to both sides, we get -3x=27. Dividing by -3 yields the solution x=-9.
Consider the first equation : -3x-2=25.
Adding 2 to both sides, we get -3x=27. Dividing by -3 yields the solution x=-9, again.
Thus, the 2 equations have the same solution.
We could have achieved this result also by noticing that the second equation is equivalent to first one, adding 6 to both sides.
Answer: A) The equations have the same solution because the second can be obtained by adding 6 to both sides of the first equation.
P=6
You minus the 7 from 25 and you get 18 then you divide 18 from 1/3