Jason is three roommates share the cost of the electric bill $108 evenly

If a regular triangle has a perimeter of 18x + 27 what is an expression for the length of one of its sides

marshall27 [118]

A regular triangle is a triangle with 3 equal sides. A perimeter of a triangle with 3 sides = 3 x length = 3 (length). Since you know that the perimeter is also equal to 18x + 27, therefore,

3 (length) = 18 x + 27

length = (18x + 27) / 3 <-- divided both sides by 3

length = 6x + 9

An expression for the length of one of its sides is 6x + 9.

6 0

3 years ago

Find a rational number that is between 9.5 and 9.7

Luba_88 [7]

9.5000032 is one such number

3 0

3 years ago

Read 2 more answers

Use the image to answer the question below. Which equation represents circle A?

Maksim231197 [3]

Answer is in the file below

tinyurl.com/wpazsebu

6 0

3 years ago

For the following discrete random variable X with probability distribution:

Black_prince [1.1K]

Answer:

(a) The probability distribution is shown in the attachment.

(b) The value of E (Y) is 7.85.

(c) The value of E (X) and E (X²) are 1.45 and 3.25 respectively.

(d) The value of P (Y ≤ 2) is 0.60.

(e) Verified that the value of E (Y) is 7.85.

Step-by-step explanation:

(a)

The random variable Y is defined as: $Y=3X^{2}-2X+1$

For X = {0, 1, 2, 3} the value of Y are:

$X=0;\ Y=3\times(0)^{2}-2\times(0)+1 =1$

$X=1;\ Y=3\times(1)^{2}-2\times(1)+1 =2$

$X=2;\ Y=3\times(2)^{2}-2\times(2)+1 =9$

$X=3;\ Y=3\times(3)^{2}-2\times(3)+1 =22$

The probability of Y for different values are as follows:

P (Y = 1) = P (X = 0) = 0.20

P (Y = 2) = P (X = 1) = 0.40

P (Y = 9) = P (X = 2) = 0.15

P (Y = 22) = P (X = 3) = 0.25

The probability distribution of Y is shown below.

(b)

The expected value of a random variable using the probability distribution table is:

$E(U)=\sum[u\times P(U=u)]$

Compute the expected value of Y as follows:

$E(Y)=\sum [y\times P(Y=y)]\\=(1\times0.20)+(2\times0.40)+(9\times0.15)+(22\times0.25)\\=7.85$

Thus, the value of E (Y) is 7.85.

(c)

Compute the expected value of X as follows:

$E(X)=\sum [x\times P(X=x)]\\=(0\times0.20)+(1\times0.40)+(2\times0.15)+(3\times0.25)\\=1.45$

Compute the expected value of X² as follows:

$E(X^{2})=\sum [x^{2}\times P(X=x)]\\=(0^{2}\times0.20)+(1^{2}\times0.40)+(2^{2}\times0.15)+(3^{2}\times0.25)\\=3.25$

Thus, the value of E (X) and E (X²) are 1.45 and 3.25 respectively.

(d)

Compute the value of P (Y ≤ 2) as follows:

$P (Y\leq 2)=P(Y=1)+P(Y=2)=0.20+0.40=0.60$

Thus, the value of P (Y ≤ 2) is 0.60.

(e)

The value of E (Y) is 7.85.

$E(Y)=E(3X^{2}-2X+1)=3E(X^{2})-2E(X)+1$

Use the values of E (X) and E (X²) computed in part (c) to compute the value of E (Y).

$E(Y)=3E(X^{2})-2E(X)+1\\=(3\times 3.25)-(2\times1.45)+1\\=7.85$

Hence verified.

3 0

3 years ago

There are five boys to every three girls in an introductory chinese course. if there are 384 students enrolled in the course, ho

alex41 [277]

Answer:

There are 240 boys.

Step-by-step explanation:

There are five boys to every three girls in an introductory Chinese course. Given that there are 384 students enrolled in total, we want to determine the amount of students which are boys.

Let b represent the number of boys and g girls.

Since the ratio is 5:3, we can write that:

$\displaystyle \frac{5}{3} = \frac{b}{g}$