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solong [7]
3 years ago
14

What are these answers?

Mathematics
1 answer:
Inessa05 [86]3 years ago
7 0
44
16
28
32
i think this is the answer
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What is the slope, and what is the y-intercept of the line?
Oliga [24]
General\ equation\ for\ line\ in\ slope\ intercept\ form:
\\\\y=ax+b\\
 a-slope\\ 
b-intercept\\\\ 
y=\frac{5}{4}x+9\\\\
slope=\frac{5}{4}\\\\intercept=9
4 0
3 years ago
In need of some help! Thank you in advance. 100 points <3
Anni [7]

Answer:

1

the equation (x-4)^2-17=8 has two solutions because <u>it is in a quadratic form.</u>

(x-4)^2-17=8

x²-8x+16-17-8=0

x²-8x-9=0

Doing middle term factorization

x²-9x+x-9=0

x(x-9)+1(x-9)=0

(x-9)(x+1)=0

either

<u>x=9</u>

<u>x=9or</u>

<u>x=9orx=-1</u>

2.

x^2+4x+3=0:

Doing middle term factorization

x²+3x+x+3=0

x(x+3)+1(x+3)=0

(x+3)(x+1)=0

either

x=-3

or

x=-1

<u>Josh’s solution is incorrect because he missed x=-3.</u>

<u>3</u><u>.</u>

x^2-6x+7=0

By <u>using</u><u> </u><u>quadratic</u><u> </u><u>equation</u><u> </u><u>f</u><u>o</u><u>r</u><u>m</u><u>u</u><u>l</u><u>a</u><u>:</u>

Comparing above equation with ax²+bx+c=0

we get

a=1

b=-6

c=7

Now

we have

x=\frac{ - b ±  \sqrt{ {b}^{2}  - 4ac} }{2a}

x=\frac{ 6±  \sqrt{ {-6}^{2}  - 4*1*7} }{2}

x=\frac{ 6±2\sqrt{ 2}}{2}

x={ 3±\sqrt{ 2}}

Taking positive

<u>x</u>={ 3+\sqrt{ 2}}

taking negative

<u>x</u>={ 3-\sqrt{ 2}}

4 0
3 years ago
-4+2(12)<br> ————<br> -3(-3)-(-1)
dsp73

Answer:

20/10 is 2

final answer is 2

8 0
3 years ago
The solution x=7 is a solution to which of the following equations
lbvjy [14]
We need the equations.

6 0
4 years ago
10 points Help Me Please I will give brainiest​
Effectus [21]

Answer:

The slope is 1/2

Step-by-step explanation:

To find the slope you use the formula rise/run

The rise is the second y coordinate minus the first y coordinate

The run is the second x coordinate minus the first y coordinate

Step one:

Take 2 points: I used (2,1) and (4,2)

Step two:

Use the formula

2-1/4-2

The answer is the slope of the line

The slope is 1/2

5 0
3 years ago
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