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Oduvanchick [21]

4 years ago

9

In the late 1920s, what did the Federal Reserve refuse to do in order to keep a run on the banks from causing a failure of the U

S banking system?

Advanced Placement (AP)

1 answer:

Nutka1998 [239]4 years ago

3 0

Answer:

They refused to enact a loose monetary policy.

Explanation:

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A movie theater chain has lost business during a global health crisis. They are surveying a SRS of 70 customers

Makovka662 [10]

Answer:

The sampling distribution of (P a- P b) will not be normal, because we expect fewer than 10 customers who do not want to order tickets digitally in both samples.

Explanation:

khan

8 0

3 years ago

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A men’s health magazine would like to conduct a survey using a simple random sample of 900 men who practice yoga. One of the goa

saw5 [17]

Answer: B) The width of the interval based on 100 men would be about three times the width of the interval based on 900 men.

Explanation:

Based on the information given, if there's no change in the sample proportion, the option that best describes the anticipated effect on the width of the confidence interval assuming the magazine surveyed a random sample of 100 men who practice yoga, rather than 900 men will be option B "The width of the interval based on 100 men would be about three times the width of the interval based on 900 men.

Therefore, the correct option is B.

4 0

3 years ago

In what way is Grandma's lodger, Bill Galvin, unusual?

xeze [42]

Answer:

He does not drink Guinness. He is kind to Frank.

Explanation:

6 0

3 years ago

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Please create a planning sheet I’m so behind in my classes please and thank you

Nuetrik [128]

Answer:

yes drinking alcohol is bad for your health and cause numerous side effects like lung disease, diabetes, heart disease, heart failure, etc... ._.

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3 0

3 years ago

AP CALC QUESTION!! WILL MARK BRAINLIEST (TWO QUESTIONS)

kodGreya [7K]

1. Using washers, the volume is given by the integral

$\displaystyle\pi\int_1^{e^2}((2+2)^2-(\ln x+2)^2)\,\mathrm dx$

$=\boxed{\displaystyle\pi\int_1^{e^2}(20+4\ln x-(\ln x)^2)\,\mathrm dx}$

We're using washers whose centers depend on the value of $x$ , hence we integrate with respect to

2. The area of the given region is given by the integral

$\displaystyle\int_0^2\sin^{-1}\frac x2\,\mathrm dx$

To compute the integral, first consider the substitution $u=\frac x2$ , or $2u=x$ so that $2\,\mathrm du=\mathrm dx$ . Then $x\to0\implies u\to0$ and $x\to2\implies u\to1$ , so the integral is equivalently

$\displaystyle2\int_0^1\sin^{-1}u\,\mathrm du$

Integrate by parts, taking

$f=\sin^{-1}u\implies\mathrm df=\dfrac{\mathrm du}{\sqrt{1-u^2}}$

$\mathrm dg=\mathrm du\implies g=u$

so that

$\displaystyle2\int_0^1\sin^{-1}u\,\mathrm du=2\left(u\sin^{-1}u\bigg|_0^1-\int_0^1\frac u{\sqrt{1-u^2}}\,\mathrm du\right)$

$\sin^{-1}0=0$ and $\sin^{-1}1=\frac\pi2$ , so the area is

$\displaystyle\pi-2\int_0^1\frac u{\sqrt{1-u^2}}\,\mathrm du$

For the remaining integral, substitute $w=1-u^2$ , so that $\mathrm dw=-2u\,\mathrm du$ . Then $u\to0\implies w\to1$ and $u\to1\implies w\to0$ :

$\displaystyle\pi-\int_0^1\frac{\mathrm dw}{\sqrt w}$

(notice that the integral is improper)

$\displaystyle\pi-\lim_{t\to0^+}2\sqrt w\bigg|_t^1$

$\displaystyle\pi-2\left(1-\lim_{t\to0^+}\sqrt t\right)=\boxed{\pi-2}$

8 0

3 years ago