3 years ago

Calculate the mean given the frequency table

Mathematics

1 answer:

asambeis [7]3 years ago

4 0

Answer:0-9

10-19

20-29

Step-by-step explanation:

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/13 Quiz High School Math Focus Practice ItemsQuestion 2 of 15Question 2 (1 point)Consider this right triangle. Enter the measur

Oliga [24]

Solution

Step 1

For a given angle A

Opposite = 12

Hypotenuse = 15

Step 2

$\begin{gathered} sinA\text{ = }\frac{Opposite}{Hypotenuse} \\ sinA\text{ = }\frac{12}{15} \\ A\text{ = sin}^{-1}(\frac{12}{15}) \\ A\text{ = 53} \end{gathered}$

Final answer

A = 53

7 0

1 year ago

What is the length of BC in the right triangle below?

11Alexandr11 [23.1K]

22 squared + 120 squared
14484
rad 14484 equals 122
the answer is b

6 0

3 years ago

Read 2 more answers

Simplify:<br>1/1-x^(b-a)+1/1-x^(a-b)

Pachacha [2.7K]

Answer:

Step-by-step explanation:

simplify:

1/1-x^(b-a)+1/1-x^(a-b)

$\frac{1}{1-x^{b-a}} + \frac{1}{1-x^{a-b}}\\= \frac{1-x^{a-b} + 1-x^{b-a}}{(1-x^{b-a})(1-x^{a-b})}\\= \frac{1-x^{a-b} + 1-x^{b-a}}{(1-x^{b-a}-x^{a-b}+x^{b-a+a-b})}\\= \frac{1-x^{a-b} + 1-x^{b-a}}{(1-x^{b-a}-x^{a-b}+1)}\\= \frac{2-x^{a-b}-x^{b-a}}{2-x^{b-a}-x^{a-b}}\\= 1\\ \\$