Answer:
b) ? = 0
c) ? = 10
Step-by-step explanation:
By observing the equations, we notice a pattern. The resulting number is always equal to one number doubled added to the other number. Therefore, set up two equations as follows:
2(7)+y=14
2x+3=23
Assume that the provided number is the doubled number if it is a perfect factor, with 2, and assume the provided number is not the provided number if the difference between the answer and it is an even number.
Solve:
14+y=14
y=0
2x+3=23
2x=20
x=10
Answer:
y= -1/2x
Step-by-step explanation:
y-y1/x-x1=y2-y1/x2-x1
y-1/x+2=-1/2
2y-2= -x-2
2y= -x-2+2
2y=-x
y=-1x/2„
Answer:
4x^2+3x-6
Step-by-step explanation:
Answer:
3x + 70 − 7x ≥ 18
Step 1: Simplify both sides of the inequality.
−4x + 70 ≥ 18
Step 2: Subtract 70 from both sides.
−4x + 70 − 70 ≥ 18 − 70
−4x ≥ −52
Step 3: Divide both sides by -4.
−4x
/−4 ≥ −52
/−4
x ≤ 13
Answer: The correct answer is option C: Both events are equally likely to occur
Step-by-step explanation: For the first experiment, Corrine has a six-sided die, which means there is a total of six possible outcomes altogether. In her experiment, Corrine rolls a number greater than three. The number of events that satisfies this condition in her experiment are the numbers four, five and six (that is, 3 events). Hence the probability can be calculated as follows;
P(>3) = Number of required outcomes/Number of possible outcomes
P(>3) = 3/6
P(>3) = 1/2 or 0.5
Therefore the probability of rolling a number greater than three is 0.5 or 50%.
For the second experiment, Pablo notes heads on the first flip of a coin and then tails on the second flip. for a coin there are two outcomes in total, so the probability of the coin landing on a head is equal to the probability of the coin landing on a tail. Hence the probability can be calculated as follows;
P(Head) = Number of required outcomes/Number of all possible outcomes
P(Head) = 1/2
P(Head) = 0.5
Therefore the probability of landing on a head is 0.5 or 50%. (Note that the probability of landing on a tail is equally 0.5 or 50%)
From these results we can conclude that in both experiments , both events are equally likely to occur.
