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Vanyuwa [196]
3 years ago
14

How do I solve this?

Mathematics
1 answer:
Anni [7]3 years ago
3 0
I hope this helps you




4^3/3.x^2/3.y^3/3


4.y.x^2/3
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In a box there are six envelopes each containing two cards. Three of the envelopes contain two red cards, two of them contain a
Sphinxa [80]

Answer:

\frac{2}{5}

Step-by-step explanation:

3 envelopes having 2 red card

2 envelopes having 1 red card and 1 black card

1 envelope having 2 black cards

We are given that . An envelope is selected at random and a card is withdrawn and found to be red.

So, No. of ways of envelope having red card = 3+2 = 5

No. of required ways of envelope having 1 red card and 1 black card = 2

So, probability of getting an envelope having 1 red card and 1 black card = \frac{2}{5}

Hence The chance the other card is black is \frac{2}{5}

5 0
3 years ago
Given the following: P(A) =0.3 P(B) = 0.2 P(A OR B) = 0.5 P(A AND B) = 0 Which of the following is true?a. A and B are disjoint.
erastova [34]

Answer:

a. A and B are disjoint

Step-by-step explanation:

We know that P(A and B)=0, It means that event A and event B have nothing in common and it means that event A and event B are disjoints events.

The event A and event B are independent if

P( A and B)= P(A)*P(B)

P(A)*P(B)=0.3*0.2=0.06

So, P(A and B)≠P(A)*P(B)

Hence events A and B are not independent.

Option a is A and B are disjoints which is correct

Option b is A and B are neither disjoints nor independent which is partially false as A and B are disjoints event.

Option c states that A and B are independent which is clearly false.

Option d states that A and B are disjoints and independent which is partially false as A and B are not independent.

Hence the correct option is option A.

5 0
3 years ago
Can someone solve this
marysya [2.9K]

From the Arithmetic Information given, Pr = 0.049375 ≠ -8.050625 ≠ 0.0325  See explanation below.

<h3>

What are the step by steps solution to the questions above?</h3>

First, lets us restate the question properly. We have

Pr = 1 - ((6*12+6)/80)² = 1 - ((9*12²)/1600) - ((3*12*6)/1600) - (6²/6400) = 1 - 0.005625 * 12² - 0.001875 * 12 * 6 - 0.00015625 * 6²

Note that there are three equals signs. So lets divide the problem according and solve for the different parts.

Lets   1 - ((6*12+6)/80)²  ............A

1 - ((9*12²)/1600) - ((3*12*6)/1600) - (6²/6400) .............B; and

1 - 0.005625 * 12² - 0.001875 * 12 * 6 - 0.00015625 * 6² ........C

Solving for A we have

1 - (78/80)²

= 1 - (0.975)²

= 1 - 0.950625

A = 0.049375


Solving for B we have

1 - ((9*12²)/1600) - ((3*12*6)/1600) - (6²/6400)

= 1- (14,256/1600) - (216/1600) - (36/6400)
= 1 - 8.91 - 0.135 - 0.005625

B = -8.050625

Solving for C we have

1 - 0.005625 * 12² - 0.001875 * 12 * 6 - 0.00015625 * 6²

= 1 - 0.005625 * 144 - 0.001875 * 12 * 6 - 0.00015625 * 144

= 0.0325


In summary we can state that:

A = 0.049375

B =  -8.050625

C = 0.0325

Given that there were no abstract quantities, we can state that

Pr = A ≠ B ≠C or

Pr = 0.049375 ≠ -8.050625 ≠ 0.0325

Learn more about equations with equal signs at

brainly.com/question/18924248
#SPJ1

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pam uses 1 half cup of milk for each milkshake if she makes 18 milk shakes how many cups of milk does she use
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I am not going to give you the answer, but I am going to tell you how to do it. You first put 18 over 1, and multiply that by one half. (You multiply across.)
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