Answer:
A Rational number is a number that can be written as a ratio in fraction form.
An Irrational number is a number that, when in decimal form, does not terminate or repeat.
Step-by-step explanation:
1.485 can be written as 1 485/1000 - it is rational
0.187345911... continues on and does not repeat - it is irrational
333.051422218... continues on and does not repeat - it is irrational
0.2268715 can be written as 2268715/10000000 - it is rational
1.24 can be written as 1 24/100 - it is rational
i think A because delation of scale factor 2
Answer:
Step-by-step explanation:
For this equation: a=3, b=4, c=2
3x2+4x+2=0
Step 1: Use quadratic formula with a=3, b=4, c=2.
x= −b±√b2−4ac / 2a
x= −(4)±√(4)2−4(3)(2) / 2(3)
x= −4±√−8 / 6
Answer:
No real solutions.
Answer:
1,215 Superscript one-fifth x
Step-by-step explanation:
Given:
The expression to simplify is given as:
![(\sqrt[5]{1215})^x](https://tex.z-dn.net/?f=%28%5Csqrt%5B5%5D%7B1215%7D%29%5Ex)
We know that,
![\sqrt[n]{a} = a^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%20%3D%20a%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
Here, 
So, ![\sqrt[5]{1215} = 1215^{\frac{1}{5}}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B1215%7D%20%3D%201215%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D)
So, the above expression becomes:
![(\sqrt[5]{1215})^x = (1215^{\frac{1}{5}})^x](https://tex.z-dn.net/?f=%28%5Csqrt%5B5%5D%7B1215%7D%29%5Ex%20%3D%20%281215%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D%29%5Ex)
Now, using the law of indices 
Here, 
So, the expression is finally simplified to;
Therefore, the second option is the correct one.
= 1,215 Superscript one-fifth x
