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Annette [7]
3 years ago
7

A restaurant chef ordered 4 pounds of beef at $3.25 per pound, 6 pounds of potatoes at $1.96 a pound, and 5 pounds of carrots at

$1.81 per pound. He estimates that this will make 28 meals. If he charges $20 per meal, how much profit will he make for each meal?
Mathematics
1 answer:
zhenek [66]3 years ago
3 0

Answer:

Profit = $18.8 per meal

Step-by-step explanation:

Chef ordered beef = 4 pounds

Cost of beef = $3.25 per pound

Total cost of beef = 4 × 3.25 = $13

Amount of potatoes ordered = 6 pounds

Cost of potatoes = $1.96 per pound

Total cost of potatoes = 6 × 1.96

                                     = $11.76  

Amount of carrots ordered = 5 pounds

Cost of carrots = $1.81 per pound

Total cost of carrots = 5 × 1.81 = $9.05

Total amount of beef, potatoes and carrots = $13 + $11.76 + $9.05

                                                                        = $33.81

Number of meals prepared with material purchased = 28

Per meal cost = \frac{33.81}{28} = $1.2075

Selling price of one meal = $20

Profit per meal = Selling price - Cost price

                         = 20 - 1.2075

                         = 18.7925

                         ≈ $18.8

Therefore, he will make $18.8 for each meal.

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Anon25 [30]

Answer:

A. -16x²+64x+8

B. 72 ft.

Step-by-step explanation: A. Expand the perfect square binomial -16(x²-4x+4)+72, dist. -16 (-16x²+64x-64+72), then combine like terms (-16x²+64x+8)

B. Find the abs. max. by looking back at the vertex form. The max is (2,72). Use the y-value for the height.

3 0
3 years ago
What kind of sequence is the pattern 1, 6, 7, 13, 20, ...?
AlexFokin [52]

Answer:

The given sequence 6, 7, 13, 20, ... is a recursive sequence

Step-by-step explanation:

As the given sequence is

6, 7, 13, 20, ...

  • It cannot be an arithmetic sequence as the common difference between two consecutive terms in not constant.

As

d = 7-6=1,  d = 13-7=6

As d is not same. Hence, it cannot be an arithmetic sequence.

  • It also cannot be a geometrical sequence and exponential sequence.

It cannot be geometric sequence as the common ratio between two consecutive terms in not constant.

As

r = 7-6=1,  r = 13-7=6

r = \frac{7}{6},  r = \frac{13}{7}

As r is not same, Hence, it cannot be a geometric sequence or exponential sequence. As exponential sequence and geometric sequence are basically the same thing.

So, if we carefully observe, we can determine that:

  • The given sequence 6, 7, 13, 20, ... is a recursive sequence.

Please have a close look that each term is being created by adding the preceding two terms.

For example, the sequence is generated by starting from 1.

     {\displaystyle F_{1}=1

and

     {\displaystyle F_{n}=F_{n-1}+F_{n-2}}

for n > 1.

<em>Keywords: sequence, arithmetic sequence, geometric sequence, exponential sequence</em>

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6 0
3 years ago
5
Svetradugi [14.3K]

Answer:

The right answer is:

Option OB: f(1) = -9

Common difference: 7

Step-by-step explanation:

Given sequence is:

-9, -2, 5, 12,...

Here the first number is f(1)

Common Difference:

Common difference is the difference between consecutive terms of an arithmetic sequence. It is denoted by d.

In the given sequence,

f(1) = -9

f(2) = -2

f(3) = 5

d=f(2)-f(1) = -2-(-9) = -2+9 = 7\\d = f(3)-f(2) = 5-(-2) = 5+2 = 7

Hence,

The right answer is:

Option OB: f(1) = -9

Common difference: 7

7 0
2 years ago
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DaniilM [7]
5 whshfunrkfnrj sjdbe
8 0
3 years ago
Ray has found that his new car gets 31 miles per gallon on the highwayand 26 miles per gallon in the city. He recently drove 285
Mkey [24]

Answer:

Highway = 155\ miles

City = 130\ miles

Step-by-step explanation:

Given

Highway = 31mi/gallon

City = 26mi/gallon

Total\ Miles = 285

Total\ Gallons = 10

Required

Determine the number of miles driven on the highway and on the city

Represent the gallons used on highway with h and on city with c.

So, we have:

c + h = 10 ---- gallons used

and

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In the first equation, make c the subject

c = 10 - h

Substitute 10 - h for c in the second equation

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31h + 26(10 - h) = 285

Open bracket

31h + 260 - 26h = 285

Collect like terms

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5h = 25

Make h the subject

h = \frac{25}{5}

h = 5

Substitute 5 for h in c = 10 - h

c = 10 - 5

c = 5

If on the highway, he travels 31 miles per gallon, then his distance on the highway is:

Highway = 31 * 5

Highway = 155\ miles

If in the highway, he travels 26 miles per gallon, then his distance on the highway is:

City = 26 * 5

City = 130\ miles

8 0
3 years ago
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