All categories

3 years ago

True or false? And why? The value of |x +1| is greater than or equal to 0

Mathematics

1 answer:

goldfiish [28.3K]3 years ago

4 0

True.

The absolute value of anything is the distance that value is away from zero.

For instance, |-5 + 1| = 4

As we can see, any number that we plug into this equation will always be a number equal to or greater than zero.

You might be interested in

The lengths of salamanders have a normal distribution with mean 15cm, and standard deviation 2cm. What length of salamander woul

Law Incorporation [45]

Answer:

16.68 cm

Step-by-step explanation:

Given that :

Mean , m = 15

Standard deviation, s = 2

Length of salamander that would Place it at 80% of salamander length :

P(Z ≤ x) = 0.8

Zscore equivalent to 0.8 = 0.842

Using the relation :

Zscore = (x - m) /s

0.842 = (x - 15) / 2

1.684 = x - 15

Add 15 to both sides

1.684 + 15 = x - 15 + 15

16.684 = x

Hence, x = 16.68 cm

4 0

3 years ago

The distance between City A and City B is 250 miles. A length of 2.3 feet represents this distance on a certain wall map. City C

masya89 [10]

The distance between city C and city D is 450 miles.

Solution:

Given, The distance between City A and City B is 250 miles.

A length of 2.3 feet represents this distance on a certain wall map.

City C and City D are 4.14 feet apart on this map.

We have to find what is the actual distance between City C and City D?

Now, distance between a and b is 250 miles ⇒ 2.3 feet on map

Then, distance between c and d be n miles ⇒ 4.14 feet on map.

Now, by chris cross method.

250 x 4.14 = 2.3 x n miles.

2.3n = 1035

n = 450

Hence, the distance between city C and city D is 450 miles.

8 0

3 years ago

Whats the congruence of these two triangles ? none ? sas ? asa ? or sss ?

Ket [755]

Answer:

choice #3) similar by SSS

The corresponding sides do have the correct ratios.

3 0

3 years ago

Read 2 more answers

I need help on number 16 please and thank you ! For brainlest answer

marusya05 [52]

M5 is the same as m1 so it's 75°

6 0

4 years ago

State one form of the Law of Cosines and provide a trick for writing the other two forms and explain when Law of Cosines should

Yuki888 [10]

Solving for Angles

$\displaystyle \frac{a^2 + b^2 - c^2}{2ab} = cos∠C \\ \frac{a^2 - b^2 + c^2}{2ac} = cos∠B \\ \frac{-a^2 + b^2 + c^2}{2bc} = cos∠A$

* Do not forget to use the inverse function towards the end, or elce you will throw your answer off!

Solving for Edges

$\displaystyle b^2 + a^2 - 2ba\:cos∠C = c^2 \\ c^2 + a^2 - 2ca\:cos∠B = b^2 \\ c^2 + b^2 - 2cb\:cos∠A = a^2$

You would use this law under two conditions:

One angle and two edges defined, while trying to solve for the third edge
ALL three edges defined

* Just make sure to use the inverse function towards the end, or elce you will throw your answer off!

_____________________________________________

Now, JUST IN CASE, you would use the Law of Sines under three conditions:

Two angles and one edge defined, while trying to solve for the second edge
One angle and two edges defined, while trying to solve for the second angle
ALL three angles defined [of which does not occur very often, but it all refers back to the first bullet]

* I HIGHLY suggest you keep note of all of this significant information. You will need it going into the future.

I am delighted to assist you at any time.

7 0

3 years ago