B. Rotation
I’m assuming the question is not asking about placement but just the way the shape is.
Hope this helps!
Since f(x) is (strictly) increasing, we know that it is one-to-one and has an inverse f^(-1)(x). Then we can apply the inverse function theorem. Suppose f(a) = b and a = f^(-1)(b). By definition of inverse function, we have
f^(-1)(f(x)) = x
Differentiating with the chain rule gives
(f^(-1))'(f(x)) f'(x) = 1
so that
(f^(-1))'(f(x)) = 1/f'(x)
Let x = a; then
(f^(-1))'(f(a)) = 1/f'(a)
(f^(-1))'(b) = 1/f'(a)
In particular, we take a = 2 and b = 7; then
(f^(-1))'(7) = 1/f'(2) = 1/5
7 would probably end up being 6 12/12 if I am doing his correctly.
Answer:
$90.75
Step-by-step explanation:
103*100=(13.5%+100%)*x
10300=113.5x
x=10300/113.5
x=90.74889868
x=$90.75
X=kevin
<span>y=steve </span>
<span>x+y=26 </span>
<span>x=4+y </span>
(4+y)+y=26
<span>-4 -4 </span>
<span>y+y=22 </span>
2y=22
<span>/2 /2
</span>
<span>y=11 </span>
<span>steve ran 11 miles</span>
