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bogdanovich [222]

2 years ago

8

Meal A has 170 calories in 3 servings. Meal B has 160 calories

1 answer:

leva [86]2 years ago

4 0

Meal A had mor calories

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Is 2CO + 2NO → 2CO2 + N2 balanced

Advocard [28]

Yes, the equation is balanced. (brainliest?)

7 0

3 years ago

The expression 8x2 − 144x 864 is used to approximate a small town's population in thousands from 1998 to 2018, where x represent

Rzqust [24]

The expression that is most useful for finding the year where the population was at a minimum would be 8(x − 9)² + 216.

Given expression 8x² − 144x + 864 is used to approximate a small town's population in thousands from 1998 to 2018, where x represents the number of years since 1998.

<h3>What is a quadratic equation?</h3>

A quadratic equation is the second-order degree algebraic expression in a variable. the standard form of this expression is ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.

Given expression is 8x² − 144x + 864

Let y = 8x² − 144x + 864

also, y - 864 = 8x² - 144x

by Extracting common factor 8 on the right side

y - 864 = 8(x² - 18x)

Add (18/2)² on both sides, we get

y - 864 + 8(18/2)² = 8 (x² - 18x + 81²)

y - 864 + 648 = 8 (x² - 8x + 9)

on simplification

y - 216 = 8 (x - 9)²

y = 8(x - 9)² + 216

therefore, y = 8 (x - 9)² + 216

The expression that is most useful for finding the year where the population was at a minimum would be 8(x − 9)² + 216.

Learn more about a quadratic equation here:

brainly.com/question/2263981

8 0

1 year ago

Find the sum of each series, if it exists<br>91 + 85 + 79 + … + (29)

Natali [406]

Answer:

651.

Step-by-step explanation:

Note: In the given series it should be -29 instead of 29 because 29 cannot be a term of AP whose first term is 91 and common difference is -6.

Consider the given series is

$91+85+79+...+(-29)$

It is the sum of an AP. Here,

First term = 91

Common difference = 85 - 91 = -6

Last term = -29

nth term of an AP is

$a_n=a+(n-1)d$

where, a is first term and d is common difference.

$-29=91+(n-1)(-6)$

$-29-91=(n-1)(-6)$

$\dfrac{-120}{-6}=(n-1)$

$20=(n-1)$

$n=20+1=21$

Sum of AP is

$Sum=\dfrac{n}{2}[\text{First term + Last term}]$

$Sum=\dfrac{21}{2}[91+(-29)]$

$Sum=\dfrac{21}{2}[62]$

$Sum=651$

Therefore, the sum of given series is 651.

5 0

2 years ago

Which is equivalent to 2^3·2^-5? A) 2-15 B) 2-8 C) 2-2 D) 22

IceJOKER [234]

I hope this helps you

6 0

3 years ago

Read 2 more answers

An isosceles triangle with angles b and c having the same measure is shown. Find the measure of each angle whose degree measure

Anton [14]

Answer:

A = 114°, B = C = 33°

Step-by-step explanation:

The triangle relationships let you write two equations:

A+B+C = 180

B=C

Substituting the expressions for A, B, and C, you have ...

(x+7y+41) +(2y+13) +(6x+15) = 180

7x +9y +69 = 180

7x +9y = 111

And the second equation gives ...

(2y+13) = (6x+15)

6x -2y =-2

3x -y = -1

Now, we can add 9 times this second equation to the first to eliminate the y-variable.

(7x +9y) +9(3x -y) = (111) +9(-1)

34x = 102

x = 3

Then the angle measures are ..

B = C = 6·3+15 = 33

A = 180 -2·33 = 114

The angles in the triangle are (A, B, C) = (114°, 33°, 33°).

8 0

3 years ago