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SIZIF [17.4K]
3 years ago
10

Heights (in centimeters) and weights (in kilograms) of 7 supermodels are given below. Find the regression equation, letting the

first variable be the independent (x) variable, and predict the weight of a supermodel who is 171 cm tall.
Height 176,168,178,174,176,176,178
Weight 56,50,58,55,54,55,57
Mathematics
1 answer:
Delvig [45]3 years ago
6 0
The regression equation:
y = m x + b
m = ( 57 - 50 ) / ( 178 - 168 ) = 7 / 10 = 0.7
50 = 0.7 * 168 + b
50 = 117.6 + b
b = 50 - 117.6
b = - 67.6
y = 0.7 * x - 67.6
The graph is in the attachment.
The weight of supermodel who is 171 cm tall:
y = 0.7 * 171 - 67.6 = 119.7 - 67.6 = 52.1 kg
Download docx
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A cube-shaped tank that measures 4.64.6 meters on each side is full of water. If some water is drained to fill a cone with a hei
rusak2 [61]

Answer:

The amount of water left in the tank is approximately 58.1 cubic meters

Step-by-step explanation:

step 1

Find the volume of the a cube shape tank

The volume is equal to

V=b^{3}

we have

b=4.6\ m

substitute

V=4.6^{3}=97.336\ m^{3}

step 2

Find the volume of cone

The volume is equal to

V=\frac{1}{3}\pi r^{2}h

we have

r=2.5\ m

h=6\ m

\pi =3.14

substitute

V=\frac{1}{3}(3.14)(2.5)^{2}(6)

V=39.25\ m^{3}

step 3

Find the difference of the volumes

97.336\ m^{3}-39.25\ m^{3}=58.1\ m^{3}

3 0
3 years ago
If logb2=x and logb3=y, evaluate the following in terms of x and y:
Alja [10]

log_b{162} = x + 4y\\\\log_b324 = 2x+4y\\\\log_b\frac{8}{9} = 3x-2y\\\\\frac{log_b27}{log_b16} = 3y-4x

<em><u>Solution:</u></em>

Given that,

log_b2 = x\\\\log_b3 = y --------(i)

<em><u>Use the following log rules</u></em>

Rule 1: log_b(ac) = log_ba + log_bc

Rule 2: log_b\frac{a}{c} = log_ba - log_bc

Rule 3: log_ba^c = clog_ba

a) log_b{162}

Break 162 down to primes:

162 = 2^1 \times 3^4

log_b{162} =log_b 2^1. 3^4\\\\By\ rule\ 1\\\\ log_b{162} = log_b 2^1 +log_b 3^4\\\\By\ rule\ 3\\\\1log_b2 + 4log_b3\\\\1x+4y\\\\x+4y

Thus we get,

log_b162 = x + 4y

Next

b) log_b 324

Break 324 down to primes:

324 = 2^2 \times 3^4

log_b324 = log_b 2^2.3^4\\\\By\ rule\ 1\\\\log_b324 = log_b2^2 + log_b3^4\\\\By\ rule\ 3\\\\log_b324 = 2log_b2 + 4log_b3\\\\From\ (i)\\\\log_b324 = 2x + 4y

Next

c) log_b\frac{8}{9}

By rule 2

log_b\frac{8}{9} = log_b8 - log_b9\\\\log_b\frac{8}{9} = log_b 2^3 - log_b3^2\\\\By\ rule\ 3\\\\log_b\frac{8}{9} =  3 log_b2 - 2log_b3\\\\From\ (i)\\\\log_b\frac{8}{9} =  3x - 2y

Next

d) \frac{log_b27}{log_b16}

By rule 2

\frac{log_b27}{log_b16} = log_b27 - log_b16\\\\ \frac{log_b27}{log_b16} = log_b3^3 - log_b2^4\\\\By\ rule\ 2\\\\ \frac{log_b27}{log_b16} = 3log_b3 - 4log_b2 \\\\From\ (i)\\\\\frac{log_b27}{log_b16} =  3y - 4x

Thus the given are evaluated in terms of x and y

3 0
2 years ago
Please help asap 30 pts
motikmotik

Answer:

20 or D.

Step-by-step explanation:

You simply plug in the values given for a and b:

4(5)+7(-3)+3(5)-2(-3) = 20-21+15+6=20

So, your answer is 20.

5 0
3 years ago
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Masja [62]

Answer:

-7

Step-by-step explanation:

7 0
3 years ago
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Greeley [361]
X is 65 because 65 is great and should always be the answer

8 0
3 years ago
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