The answer for your problem is shown on the picture.
Answer:
Step-by-step explanation:
Use the info given in the exponential equation to find the value of b, the rate of decay.
where v(t) is the value of the car after a certain number of years, t, have gone by, a is the initial value, and b is the rate of decay. We have everything we need but b:
a = 20000
v(t) = 16000 after t = 1 year:
so
b = .8 Taken in context, this means that the car depreciates 20% each year. Now we can solve the problem being asked of us, which is to find the value of the car after t = 5 years:
which simplifies down a bit to
v(t) = 20000(.32768) so
v(t) = 6553.60, choice C.
I must assume that you meant t=1 (not t=?1). If t=1, here's what we'd do:
1. Find the x and y values corresponding to t=1. They are:
x=(1)^7+1=2 and y=(1)^8+1=2. (Please note: write t^8 instead of t8, and write t^7 instead of t7.)
2. The slope of the tangent line to the graph is
dy/dt 8t^7+1
dy/dx = ---------- = ---------------- with 1 substituted for t
dx/dt 7t^6
Thus, dy/dx (at t=1) = 9/7
3. Now we have both a point (2,2) on the graph and the slope of the tangent line to the curve at that point: 9/7
4. The tangent line to the curve at (2,2) is found by using the point-slope formula:
y-y1 = m(x-x1)
which comes out to y-2 = 9/7(x-2), or 7y-14 = 9(x-2). You could, if you wished, simplify this result further (e. g., by solving for y in terms of x).
Answer:
A) 3500
Step-by-step explanation:
C(x) = 0.75x + 3500
C(x) = Total cost
0.75x = variable cost
3,500 = fixed cost
The fixed cost of the function = 3,500
Variable cost refers to cost of production that changes during production such as cost of raw material, wages of workers etc.
Fixed cost are cost of production that remains the same (does not change) with the production process such as building, machineries etc
Total cost is the addition of all cost of production, that is, the addition of fixed cost and variable cost
Answer:
since 20% is 100
then 80% is 400
Therefore 500 in total to begin with.
