The longest possible altitude of the third altitude (if it is a positive integer) is 83.
According to statement
Let h is the length of third altitude
Let a, b, and c be the sides corresponding to the altitudes of length 12, 14, and h.
From Area of triangle
A = 1/2*B*H
Substitute the values in it
A = 1/2*a*12
a = 2A / 12 -(1)
Then
A = 1/2*b*14
b = 2A / 14 -(2)
Then
A = 1/2*c*h
c = 2A / h -(3)
Now, we will use the triangle inequalities:
2A/12 < 2A/14 + 2A/h
Solve it and get
h<84
2A/14 < 2A/12 + 2A/h
Solve it and get
h > -84
2A/h < 2A/12 + 2A/14
Solve it and get
h > 6.46
From all the three inequalities we get:
6.46<h<84
So, the longest possible altitude of the third altitude (if it is a positive integer) is 83.
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Answer:
1480 feet
Step-by-step explanation:
180yd x 2 = 360yd
change to feet: 360 x 3 = 1080 feet
200ft x 2 = 400ft
1080 + 400 = 1480ft
Answer:
Slope is -3, y-intercept is 30
Step-by-step explanation:
You take the two points (11,-3) and (7,9), plug them into the formula y2-y1/x2-x2=m. Now, you have 9-(-3)/7-11 which gives you 12/-4, 12/-4 can be simplified into -3 which is your slope. To find y-intercept you must use the formula y=mx+b. Plug -3, your slope, into m, and any of the coordinates on your line into the y and x; I used (7,9). You solve for b from 9=-3*7+b. -3*7 gives you -21, now you have 9=-21+b, to get b by itself, you add 21 to both sides, 30=b. B is your y-intercept.
Answer:
D.
Step-by-step explanation:
All other equations have x or y to the power of one so they are linear. D. has x or y to the power of two, so it's not linear. Quadratics and any variable to the power of 2 and above is not linear (numbers on their own are also always linear, so ignore any powers on them)
Answer:
median = total observation\ no of observation
median=2+3+2+3+2+6+13\7
median=19.857
Step-by-step explanation:
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