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pochemuha
3 years ago
15

I’m the three domain system which of the following domains includes organisms from more than one kingdom

Biology
1 answer:
Ksenya-84 [330]3 years ago
6 0

Eukarya

hope this helps :)

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Which of these gymnosperms are known to be important in maintaining the balance of carbon in an ecosystem?
CaHeK987 [17]

The correct answer is:     [D]:

___________________________________________________

                    →   " redwood tree forests " .

___________________________________________________

 <u>Note</u>:  Let us consider the other answer choices.

___________________________________________________

Choice:  [A]:  "garden flowering plants" ;  is incorrect  — since these are not generally considered to be part of a true or traditional "ecosystem" ; and especially since "garden flowering plants" are, in fact, "flowering plants" —  which means that they are "angiosperms" —  <em><u>Not</u></em>  "<em><u>gymnosperms</u></em><em> </em>".

      →  Rule out:  " Choice:  [A] " .

__________________________________________________

Choice:  [B]:  " ferns and liverworts " ; is incorrect — since <em><u>both</u></em>  ferns — as well as liverworts —<u><em> are Not  </em></u><u>"</u><u><em>gymnosperms </em></u>".  

          Liverworts are "bryophytes" {which lack true vascular tissue] ; and ferns are "pterophytes" ["seedless vascular plants"].

      →  Rule out:  " Choice:  [B] " .

___________________________________________________

Choice:  [C]: " mosses and horsetails "; is incorrect ;  since <em><u>both</u></em> mosses — as well as horsetails — <u><em>are Not  </em></u><u>"</u><u><em>gymnosperms </em></u>".   Mosses are "bryophytes" (see aforementioned) ; and horsetails are "non-seed bearing plants" that spread vegetatively [underground; by asexual reproduction — <em><u>and Not by seed</u></em><em> .</em>].

      →  Rule out:  " Choice:  [C] " .

__________________________________________________

Choice:  [D]: " redwood tree forests "  ;

               — is the only answer choice provided that is a "gymnosperm".    

             Furthermore, the "redwood tree" is a conifer (i.e. "coniferous; or, "cone-bearing" plant} that reproduces through seeds spread by "cone") — and all "conifers" are a type of "gymnosperm."  

            Furthermore, "redwood trees" grow large and tall, and redwood forest communities within an ecosystem; due to there size and presence, are:  "<em><u>known to be important in maintaining the balance of carbon in an ecosystem</u></em>."

__________________________________________________

 →  As such, the correct answer is:

__________________________________________________

 →  Answer choice:  [D]:  " redwood tree forests " .

__________________________________________________

Hope this helps!

    Best wishes to you in your academic endeavors

           — and within the "Brainly" community!

__________________________________________________

5 0
3 years ago
Read 2 more answers
Why is palmitic acid called a saturated fatty acid?
Sholpan [36]
Palmitic acid is considered a saturated fatty acid since it has no double bond in its structure and is solid at room temperature. It is a long-chain fatty acid with 16-Carbon backbone. It is typically found in fats and waxes such as olive oil and palm oil.
6 0
3 years ago
The movement of sand from one place to another:
xxMikexx [17]

Answer:

the movement is called as saltation

Explanation:

hope it helps...

6 0
3 years ago
Read 2 more answers
The brain volumes ​(cm cubed​) of 20 brains have a mean of 1116.2 cm cubed and a standard deviation of 127.7 cm cubed. Use the g
Shkiper50 [21]

Answer:

Yes

Explanation:

Range rule of thumb predicts the Range to be  a multiple of 4 of the standard deviation or to be four times  the standard deviation. Making the usual values equal to 2 standard deviations distanct of the mean of the data distribution.

In a given distribution with mean and standard deviation that is obtained, the usual values in mean (as seen in the attached image).

2*standard deviation and mean + 2*standard deviation.

If the data point is not up to the mean

- 2* standard deviation is taken to be significantly low.

If the data point is more than the mean

+ 2*standard deviation is taken to be significantly high.

Let's take the xbar to be the mean and s as standard deviaiton

Given,

mean, xbar = 1116.2

standard deviation, s =127.7

The range rule of thumb shows that the usual values are within 2 standard deviations from the mean

Lower boundary

      = xbar - 2s

       = 1116.2 - 2(127.7)

       = 860.8

Upper boundary

      = xbar + 2s

       = 1116.2 + 2(127.7)

       = 1371.6

We should note that 1411.6 is not between 860.8 and 1371.6, which connotes that 1411.6cm^3 is unusually high.

3 0
3 years ago
HURRY 50 PTS
Talja [164]

unsaturated fatty acids

omega-3 fatty acids

those are the good ones

5 0
3 years ago
Read 2 more answers
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